Timeline for Quantum State Function $\psi$
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Mar 5, 2014 at 18:22 | comment | added | Wildcat | @Ruslan, true. I meant that $\cos(6 \pi x)$ is not square-integrable on the whole real line, so it can't be the wave function for a particle not confined to some region of space a priori. | |
| Mar 5, 2014 at 16:57 | comment | added | Ruslan | @Wildcat it could be a wavefunction for infinite potential well, $x\in[-\frac14,\frac14]$, for example. There it'd be square integrable. | |
| Mar 5, 2014 at 13:51 | comment | added | Wildcat | I still think $\cos(6 \pi x)$ is just an example in the question, though a bad one, since this function is not square-integrable. | |
| Mar 5, 2014 at 13:45 | comment | added | Wildcat | Just to note: you do not "write" a wave function, you write the Schrödinger equation and solve it. The solution is the wave function. A function is not a wave function unless it is a solution of the Schrödinger equation for some physical system. | |
| Mar 5, 2014 at 13:03 | vote | accept | Isomorphic | ||
| Mar 5, 2014 at 12:58 | comment | added | garyp | The function is still not normalized. | |
| Mar 5, 2014 at 12:53 | comment | added | Wildcat | @lota You apply a Fourier transform to get the position wave function out of the momentum one, not the Born rule. | |
| Mar 5, 2014 at 12:30 | comment | added | Isomorphic | @garyp done :) . | |
| Mar 5, 2014 at 12:29 | comment | added | garyp | Since this is tagged homework, I'll ask you to take one more step: normalize the wavefunction, instead of saying "after normalization". | |
| Mar 5, 2014 at 12:28 | history | edited | Isomorphic | CC BY-SA 3.0 |
added 71 characters in body
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| Mar 5, 2014 at 12:27 | answer | added | Wildcat | timeline score: 4 | |
| Mar 5, 2014 at 12:20 | history | asked | Isomorphic | CC BY-SA 3.0 |