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Timeline for Divergent path integral

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Oct 3, 2016 at 18:35 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Aug 24, 2016 at 5:44 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Mar 3, 2016 at 6:42 answer added Souvik timeline score: 1
Mar 3, 2014 at 23:40 comment added user28355 @AlexNelson I understand that. However, what does it mean physically for a divergent path integral?
Mar 3, 2014 at 15:35 comment added Alex Nelson Presumably, it's any interaction $V(\phi)~\mathcal{O}(\phi^3)$. I'm at work, and cannot answer (perhaps @Qmechanic or someone else will give a coherent/non-tweet-lengthed response). Basically, you consider $\int\exp(S_{0}[\phi]+\int V(\phi)\,\mathrm{d}^{n}x)\, D\phi = \int\sum_{k=0}(\int V(\phi)\,\mathrm{d}^{n}x)^{k}\exp(S_{0}[\phi])\,D\phi$ then truncate the series after a couple terms, otherwise it diverges and you get infinities.
Mar 3, 2014 at 12:42 comment added Qmechanic Comment to the question (v3): What is the potential $V$?
Mar 3, 2014 at 12:41 history edited Qmechanic CC BY-SA 3.0
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Mar 3, 2014 at 3:20 history edited user28355 CC BY-SA 3.0
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Mar 3, 2014 at 1:50 comment added Alex Nelson The reason I ask about the action is: (a) you could be dealing with a "trivial infinity" from the volume of a gauge orbit; (b) it could be a legitimate infinity [e.g., the action could be unbounded from below after Wick rotating], where you would need to use Lattice approximations or effective field theory; (c) sometimes it could be "ghosts of departed quantities" when taking the continuum limit of finite differences. Can't tell which unless we see the action...
Mar 2, 2014 at 0:16 comment added Alex Nelson What's the action?
Mar 1, 2014 at 23:43 history asked user28355 CC BY-SA 3.0