Timeline for Number of the Generators of Poincare Group
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| Feb 22, 2014 at 16:35 | history | edited | rainman | CC BY-SA 3.0 |
deleted 22 characters in body
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| Feb 22, 2014 at 16:08 | comment | added | rainman | @Philip Gibbs: Thanks a lot. Authors can write one two lines more just to make things clearer :( | |
| Feb 22, 2014 at 16:00 | comment | added | Philip Gibbs - inactive | There is no "for each" relationship here. There are just 6 generators in Y and 4 in y. | |
| Feb 22, 2014 at 15:49 | comment | added | rainman | @Philip Gibbs: Then for each $Y$ there are four $y$s. And therefore we will get $6 \times 4 = 24$ generators. Where are my mistakes? | |
| Feb 22, 2014 at 12:13 | comment | added | Philip Gibbs - inactive | The components of the vector $y$ are generators too and there are $n+1=4$ of them making $6+4=10$ in total. It is as simple as that. | |
| Feb 22, 2014 at 10:14 | answer | added | Selene Routley | timeline score: 2 | |
| Feb 22, 2014 at 9:36 | vote | accept | rainman | ||
| Feb 22, 2014 at 9:22 | answer | added | joshphysics | timeline score: 5 | |
| Feb 22, 2014 at 9:17 | comment | added | rainman | @Danu: How can I get the other 4 generators according to the scheme given in Hall's book? | |
| Feb 22, 2014 at 8:22 | history | edited | rainman | CC BY-SA 3.0 |
added 3 characters in body
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| Feb 22, 2014 at 8:19 | comment | added | Danu | Physically, the other four generators come from translations in the spatial (3) and time (1) directions. | |
| Feb 22, 2014 at 8:16 | history | edited | rainman | CC BY-SA 3.0 |
added 3 characters in body
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| Feb 22, 2014 at 8:11 | history | asked | rainman | CC BY-SA 3.0 |