Is 1 liter always equal to 1 cubic decimeter, independently of temperature, pressure, etc? - Physics Stack Exchange most recent 30 from physics.stackexchange.com 2019-09-20T22:23:38Z https://physics.stackexchange.com/feeds/question/466815 https://creativecommons.org/licenses/by-sa/4.0/rdf https://physics.stackexchange.com/q/466815 2 Is 1 liter always equal to 1 cubic decimeter, independently of temperature, pressure, etc? DarioP https://physics.stackexchange.com/users/213411 2019-03-16T15:55:56Z 2019-03-16T17:24:23Z <p>I recently found <a href="http://www.endmemo.com/sconvert/mmol_m3mmol_l.php" rel="nofollow noreferrer">this conversion table</a> for the unit conversion <span class="math-container">$\rm mmol/m^3 \ \leftrightarrow\ \rm mmol/L$</span> (millimoles per cubic meter to millimoles per liter)</p> <p>My physics is very rusty, but just to be sure, is it true that a liter of liquid always corresponds to a particular volume? (i.e.: Doesn't change with regards to temperature, pressure, etc?)</p> https://physics.stackexchange.com/questions/466815/is-1-liter-always-equal-to-1-cubic-decimeter-independently-of-temperature-pres/466833#466833 2 Answer by Emilio Pisanty for Is 1 liter always equal to 1 cubic decimeter, independently of temperature, pressure, etc? Emilio Pisanty https://physics.stackexchange.com/users/8563 2019-03-16T17:15:06Z 2019-03-16T17:15:06Z <blockquote> <p>is it true that a liter of liquid always corresponds to a particular volume?</p> </blockquote> <p>Yes, this is correct. The relationship <span class="math-container">$$1\:\mathrm{L} = 10^{-3} \:\mathrm{m}^3 \tag 1$$</span> (i.e. one cubic meter is a thousand liters) is universal and it does not depend on anything. The liter is a unit of volume - by definition, it's a cubic decimeter.</p> <p>To convert between <span class="math-container">$\rm mmol/L$</span> and <span class="math-container">$\rm mmol/m^3$</span>, simply insert the relationship above: <span class="math-container">\begin{align} \rm 1\: mmol/L &amp; = \rm 1\:mmol / (10^{-3}\:m^3) \\ &amp; = \rm 10^{3}\:mmol / m^3, \end{align}</span> and vice versa.</p>