Adiabation Flame Temperature Overestimation (Hydrogen Gas) - Physics Stack Exchange most recent 30 from physics.stackexchange.com 2019-10-20T14:51:56Z https://physics.stackexchange.com/feeds/question/267233 https://creativecommons.org/licenses/by-sa/4.0/rdf https://physics.stackexchange.com/q/267233 0 Adiabation Flame Temperature Overestimation (Hydrogen Gas) John Stanford https://physics.stackexchange.com/users/123186 2016-07-10T00:34:26Z 2016-07-10T16:57:58Z <p>I'm working on some code that computes adiabatic flame temperature given a balanced equation and the relevant thermodynamic properties and I'm starting with the simplest combustion reaction I can think of: stoichiometric combustion of pure hydrogen with pure oxygen.</p> <p>$2H_2+O_2 \Rightarrow 2H_2O$</p> <p>I'm using these thermodynamic values:</p> <p>$h_{f,H_2} = 0.0 \text{ kJ/kmol}$</p> <p>$h_{f,O_2} = 0.0 \text{ kJ/kmol}$</p> <p>$h_{f,H_2O} = -241820 \text{ kJ/kmol}$</p> <p>$c_p = 1.864$ kJ/kg-K at 300K for $H_2O_{(g)}$</p> <p>$c_p = 3.217$ kJ/kg-K at 4000K for $H_2O_{(g)}$</p> <p>If the combustion equation I wrote is on a kmol basis, I get a total change in enthalpy of 483640 kJ with the combustion. If that heat goes into heating the product (water vapor), I get temperature increases ranging from 4173K to 7201K (final temperatures of 4471K and 7499K) depending on the specific heat value you use.</p> <p>$\frac{483640\text{ kJ}}{(3.217 \text{ kJ/kg-K})(36.03\text{ kg})} = 4173\text{ K}$</p> <p>$\frac{483640\text{ kJ}}{(1.864 \text{ kJ/kg-K})(36.03\text{ kg})} = 7201\text{ K}$</p> <p>When I run the code that actually considers changes in the specific heat throughout the whole heating process (interpolating based on a table at each step), I get 5024K. Even my lowest value, assuming constant specific heat at the highest value, gives a temperature increase higher than the number listed on Wikipedia, ~3500K. Am I making some kind of error or is there some kind of factor that makes the real thing different from the idealization? Thanks.</p> https://physics.stackexchange.com/questions/267233/-/267355#267355 0 Answer by user115350 for Adiabation Flame Temperature Overestimation (Hydrogen Gas) user115350 https://physics.stackexchange.com/users/115350 2016-07-10T16:57:58Z 2016-07-10T16:57:58Z <p>I thought it is related to dissociation and confirmed that from the book by Michael Liberman. </p> <p>The assumed reaction $2H_2+O_2 \Rightarrow 2H_2O$ is not true at high temperature. The molecules will dissociate to $H_2, H, O_2, O, OH, HO_2$. The dissociation reactions (e.g. $H_2O \rightarrow OH + H + O$) are endothermic and thus reduce the flame temperature. </p> <p>To calculate the adiabatic flame temperature, you may need a program such as Stanjan to include more species.</p>