1
$\begingroup$

Suppose there are two observers $A$ & $B$ both are in motion, now $A$ sees $B$ is moving with speed $'u'$. A says that another object $'d'$ is moving with speed $c+u$ w.r.t. A in the same direction as $B$. What stops him from saying this ?

The formula $\frac {u+v}{1+\frac{uv}{c^2}}$ is such that $'v'$ is speed of the object $'d'$ w.r.t.$ B$ and not $A.$ and $u$ is the speed of $B$ w.r.t. $A$, now even though $B$ also sees that the object $'d'$ moves faster than the speed of light. He can still always see light to travel with the speed of light and also he can be an inertial observer?

What is the problem here?

Improve this question
$\endgroup$
5
  • $\begingroup$ I don't know if I understood your question correctly, but what I think you are saying is the example where we can see two galaxies moving away from each other at a speed higher than c. There is no problem with that. What we cannot observe is something moving away at a speed higher than c w.r.t us. $\endgroup$
    – cinico
    Dec 20, 2013 at 11:53
  • $\begingroup$ @cinico Can you give me the proof why two bodies can't have relative velocity greater than $c$. $\endgroup$
    – Isomorphic
    Dec 20, 2013 at 11:54
  • $\begingroup$ Just look here How to deduce the theorem of addition of velocities?, you might also like: If I am travelling on a car at around 60 km/h, and I shine a light, does that mean that the light is travelling faster than the speed of light? $\endgroup$
    – jinawee
    Dec 20, 2013 at 11:57
  • $\begingroup$ Your formulation is inconsistent. You start denoting the objects by capital letters A and B, use small quoted italics for speed $'u'$ and, afterwards, say that object $'d'$ has speed $c+u$. Do you ever know what consistency ever is? $\endgroup$
    – Val
    Dec 20, 2013 at 12:00
  • $\begingroup$ @iota: two bodies can have a relative velocity greater than $c$ as viewed from some other inertial frame. They can just never see a velocity greater than $c$ relative to their own inertial frame. $\endgroup$
    – John Rennie
    Dec 20, 2013 at 12:02

2 Answers 2

Reset to default
3
$\begingroup$

Let's start with what A sees:

SR1

As per your question we'll assume that $u + v > c$, though individually $u$ and $v$ must be less than $c$ because we can never observe speeds faster than light.

Now, you are correct to say that from the perspective of A the relative velocity of B and C is greater than light. But when we talk about $c$ being the fastest speed possible we mean the fastest speed relative to the observer i.e. in this case relative to A.

The next question is what B sees:

SR2

We know B will see A moving at the speed $u$, but the question is what speed will B see C moving? Will B see C moving at a speed, $w$, faster than light? The answer is no, because this is where the equation for combining relativistic speeds applies. The speed $w$ is given by the formula you quote:

$$ w = \frac {u+v}{1+\frac{uv}{c^2}} $$

and this speed is always less than $c$.

Improve this answer
$\endgroup$
2
$\begingroup$

The situation in which A observes some object moving at a velocity $c+u$ cannot occur within the framework of special relativity, therefore your scenario is meaningless. The theory puts an upper speed limit on observable motion, which cannot even be reached by massive bodies, but only massless ones. This limit is given precisely by $c$. Hence, assuming that $u$ is positive, nothing can move at $c+u$.

Improve this answer
$\endgroup$
7
  • $\begingroup$ I just showed that in this case the two axioms of SR aren't violated here $\endgroup$
    – Isomorphic
    Dec 20, 2013 at 11:52
  • $\begingroup$ I wonder how you did that. As a simple example for why it does not make sense: take the factor gamma (which occurs in Lorentz transformations) and insert a velocity greater than c. You will end up with complex expressions, which does not make much sense. $\endgroup$
    – Frederic Brünner
    Dec 20, 2013 at 11:56
  • $\begingroup$ Take $c=2$ in some units and $u=1$ in those units. and take c+u=3. and see if v comes out to be real or complex. $\endgroup$
    – Isomorphic
    Dec 20, 2013 at 12:06
  • $\begingroup$ That is not what I was talking about. The formula for relativistic addition of velocity is derived under the assumption that Lorentz transformations are used to change between different inertial systems. But these transformations are not defined for velocities larger than c. $\endgroup$
    – Frederic Brünner
    Dec 20, 2013 at 12:10
  • 1
    $\begingroup$ The concept of an object moving faster than the speed of light is not defined. The question does not make sense. $\endgroup$
    – Frederic Brünner
    Dec 20, 2013 at 12:15

Not the answer you're looking for? Browse other questions tagged or ask your own question.