How is acceleration calculated when only the direction changes and the magnitude remains the same?
Guys, I know that my previous examples didn’t make sense and I’m sorry because I’m totally new to this topic and also I don’t think ya’ll actually understand my question.
Acceleration is change in velocity over change in time,right?
So, if the magnitude of velocity changes and the direction is same, acceleration is obviously given a value (for e.g. 2 $m/s ^2$ etc) and the direction of acceleration is the direction of change of magnitude of velocity.
My question is, what if only the direction changes? What if there’s this super advanced object that can change its direction without changing the magnitude of velocity?
How will the acceleration be calculated in that case? How can the magnitude of acceleration have value since there is no change in speed ( magnitude of velocity)?
I’m also aware about Uniform Circular Motion and how acceleration changes constantly even when the magnitude of velocity doesn’t change and how it can be calculated. But uniform circular motion is not an one dimensional direction change.
It will be of huge help if you could explain how acceleration is calculated when magnitude of velocity remains same and only direction of velocity changes in 1D motion (I.e., it goes in the opposite direction and for simplicity let’s assume that this body/object needs very little time to change its velocity from positive to negative) I’m still yet to learn calculus so if these calculations include calculus please do explain it a little in detail. Also, if an object can not change direction without changing speed in 1D motion, then please explain giving an example where the object takes very little time to change direction/ go back. I just want to know how the direction change is shown in acceleration.
Thank you for baring with me and for your time.