network profile
| bio | website | |
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| location | ||
| age | ||
| visits | member for | 1 year |
| seen | Jun 14 at 14:03 | |
| stats | profile views | 20 |
I write code in C++, Python, Java and now Haskell.
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Jun 2 |
awarded | Yearling |
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Apr 17 |
accepted | QM without complex numbers |
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Feb 4 |
awarded | Popular Question |
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Jan 7 |
accepted | Speed of sound in air |
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Jan 7 |
asked | Speed of sound in air |
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Dec 21 |
comment |
Tidal force on far side Maybe another way of seeing this: suppose Earth deforms much less than the oceans, so that the initial dark disk stays where it is. Shouldn't we see 2 bulges on both sides of that initial dark disk? |
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Dec 21 |
comment |
Tidal force on far side I've read somewhere that the asymmetry between the 2 bulges is something like 5% in the case of Earth/Moon. Also, your coordinate system seems to indicate that you are working in "Earth's frame of reference". In that frame of reference, don't we observe 2 bulges, without having to talk about the "center of figure"? |
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Dec 21 |
awarded | Critic |
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Dec 17 |
comment |
Tidal force on far side Marty - how does the free-fall show up in the equations? I was somehow under the impression that for the case of gravity, being accelerated (free-fall) or simply being in the gravity field were the same thing (I am probably confusing several things here). |
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Dec 16 |
comment |
Tidal force on far side electrostatic force is also in 1/r^2. Suppose I have two immobile spheres somewhat elastic that I can charge with opposite charges so they attract like gravity. Initially, they do not have a charge. I flip a switch, and they get charged. If the charges are strong enough, they could deform the elastic material. I would see 4 bulges, 2 on each sphere, somewhat asymmetric as per Nick, on the line of the centers, without anything moving at all. Is that correct? |
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Dec 16 |
comment |
Tidal force on far side Can you post equations here? Thanks! |
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Dec 16 |
comment |
Tidal force on far side Nick - Can you explain how you made this graphic? What software did you use? What is the model? What are the equations? - I want to try and reproduce that myself. Thanks! |
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Dec 14 |
revised |
Tidal force on far side edited tags |
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Dec 14 |
revised |
Tidal force on far side edited tags |
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Dec 14 |
revised |
Tidal force on far side edited tags |
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Dec 14 |
comment |
Tidal force on far side I think gravity is all we need and we don't need to add rotations. The bulge on the near side has to be outside the initial sphere of occupation, IMHO. From everything I could see so far on the internet, it looks like the situation is truly symmetric and the bulge on the far side is also out. It's not intuitive at all, but I think it has something to do with the Earth's reference frame not being inertial. |
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Dec 14 |
comment |
Tidal force on far side Todd - thanks for this explanation. Let me ask some further questions. Suppose that somehow A and B are perfectly still. There is no movement (I know it's not possible, but let's make this imaginary experiment). Suppose further that we can "turn on" gravitation at some point. Before we "turn on" gravitation, the 2 bodies occupy perfect spheres, and they are elastic. Now we turn on gravitation. We should see 4 bulges appear along AB, on the near and far sides of A and B. Are the bulges on the far sides inside the initial spheres that A and B occupied, or outside? I think they are outside. |
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Dec 13 |
revised |
Tidal force on far side added 8 characters in body |
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Dec 13 |
asked | Tidal force on far side |
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Aug 18 |
awarded | Scholar |
