network profile
| bio | website | |
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| location | ||
| age | ||
| visits | member for | 1 year, 1 month |
| seen | Feb 23 at 14:16 | |
| stats | profile views | 58 |
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Apr 9 |
awarded | Yearling |
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Feb 21 |
awarded | Enthusiast |
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Feb 19 |
comment |
Is that true that real quantum chaos doesn't exist? Quantum chaos is the study of the quantum behavior of classically chaotic systems. It addresses the question of what are the signatures of classical chaos in the spectra and wave functions of quantum systems |
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Feb 19 |
answered | What symmetries does a lattice calculation need to preserve? |
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Feb 8 |
comment |
Cascade in relativistic turbulence This is completely wrong. Relativistic fluid dynamics is well understood, and applied extensively to a wide range of phenomena. This includes astrophysics (supernova explosions, jets, disks, etc) and relativistic heavy ion collisions. We now know that the formalism developed in Landau and Weinberg can also be derived from the AdS/CFT correspondence. To the best of my knowledge, there is no fundamental difference between rel and non-rel turbulence, in particular the energy cascade is the same. |
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Jan 3 |
comment |
If the ground states of interacting QFTs are so complicated, how did Nature find them? The main algorithm we have for find the ground state of an interacting QFT is Euclidean lattice field theory. Simulations indicate that ground state of QCD is complex, but not hard to find (in the sense that simple Metropolis algorithms converge quickly, even if initialized with very poor guesses of the ground state). |
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Jan 3 |
comment |
If the ground states of interacting QFTs are so complicated, how did Nature find them? One minor comment: For realistic values of the quark masses the phase transition is a smooth crossover. |
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Dec 27 |
awarded | Commentator |
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Dec 27 |
comment |
Path integral with zero energy modes You would first have to include chiral fermions and a coupling to gauge fields. |
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Dec 26 |
comment |
Path integral with zero energy modes The $\omega$ are discrete Matsubara frequencies. In the case of fermions these can never be zero. For bosons, zero modes can indeed appear. This is related to Bose condensation. You can have anomalies in non-relativistic systems with a Fermi surface, but that's a more complicated story, see for example arxive:1203.2697. |
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Nov 29 |
answered | What is a bulk phase transition? |
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Nov 4 |
answered | Feynman diagrams and Hartree-Fock |
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Oct 16 |
revised |
Derivation of Ohm's Law added 20 characters in body |
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Oct 16 |
revised |
Derivation of Ohm's Law added 163 characters in body |
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Oct 16 |
answered | Derivation of Ohm's Law |
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Oct 4 |
answered | Weak isospin confinement? |
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Sep 24 |
comment |
Why water is not superfluid? A rough criterion is the condition for Bose condensation in an ideal gas, $n\lambda^3\sim 1$, where $n$ is the density and $\lambda$ is the thermal wave length. Note that your question is in some sense backwards: Helium is the exception, water is the rule. Most ordinary fluids solidify instead of becoming superfluid at low $T$. |
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Sep 24 |
answered | Why water is not superfluid? |
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Sep 17 |
awarded | Editor |
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Sep 17 |
revised |
State-dependent diffusions: Fick's law vs. Fokker-Planck's, which and why? deleted 19 characters in body |
