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| bio | website | |
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| age | ||
| visits | member for | 1 year, 2 months |
| seen | 1 min ago | |
| stats | profile views | 130 |
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4h |
revised |
Fitting a circuit scheme to a simpler model disentangle R3 and L3 from plasma impedance |
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5h |
answered | Fitting a circuit scheme to a simpler model |
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May 22 |
comment |
Why doesn't this equation for orbital motion change with position in the orbit? Nice explanation. To be cheeky, the pair of equations will indeed yield precisely two solutions: apapsis and periapsis. |
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May 22 |
comment |
Doubt on the analysis of $RC$ circuit @user1620696: You're welcome. Unfortunately, life is usually not so simple. Most circuits do not split up nicely like this one, and other techniques are required. |
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May 22 |
answered | Doubt on the analysis of $RC$ circuit |
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May 20 |
comment |
Electric power transmission @User58220: Why don't you write up your comment as an answer (since it is)? |
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May 20 |
revised |
Questions concerning some parts of the section on one-particle states in Weinberg's first volume on QFT clarity preface |
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May 20 |
comment |
Questions concerning some parts of the section on one-particle states in Weinberg's first volume on QFT @LakshyaBhardwaj: Ah, now I see. Ouch, I did not recognize that interpretation of my words. The "slow student" in question is I, not you. Sorry for any offense; none was intended. I'll edit the post. |
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May 19 |
comment |
Questions concerning some parts of the section on one-particle states in Weinberg's first volume on QFT @LakshyaBhardwaj: You're welcome (but no professors here). |
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May 15 |
awarded | Fanatic |
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May 13 |
revised |
Displacement Current - How to think of it? add a figure reference and improve the description (I hope) |
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May 13 |
comment |
Displacement Current - How to think of it? @BenCrowell: Yes, it's an awkward description. See the 2nd figure in the Wikipedia article for displacement current: en.wikipedia.org/wiki/Displacement_current , where S1 and S2 are the 2 surfaces. |
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May 13 |
answered | Displacement Current - How to think of it? |
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May 6 |
comment |
Definition of Casimir operator and its properties No problem, I was not expecting a proof, intuitive or otherwise. Your edit more than answered the mail and is much appreciated. |
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May 5 |
comment |
Definition of Casimir operator and its properties @Vibert, thanks, but we are talking about "exact definitions". |
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May 5 |
comment |
Definition of Casimir operator and its properties Nice, concise answer, as usual. (Personally, I'd like more explanation, but...) My venerable Schiff asserts that the number of Casimir invariants is equal to the maximum number of mutually commuting generators, which seems like a useful fact. Can you say how it emerges from your analysis (assuming it's true)? |
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May 5 |
comment |
Definition of Casimir operator and its properties Since, as Qmechanic notes, Casimir operators need not be quadratic, it appears that the two definitions in the question are not in fact equivalent. |
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May 5 |
comment |
Phasor representation of voltage in frequency domain @user1285419: You're welcome. Yes, $\beta x$ gives the phase characteristic of the wave as a function of position, but it has a fixed value of 0 at $x=0$. A complex amplitude permits that value to be different. |
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May 5 |
answered | Phasor representation of voltage in frequency domain |
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Apr 22 |
revised |
Faraday's law for a current loop being deformed added 817 characters in body |
