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| visits | member for | 1 year, 1 month |
| seen | 6 hours ago | |
| stats | profile views | 126 |
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1d |
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Electric power transmission @User58220: Why don't you write up your comment as an answer (since it is)? |
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1d |
revised |
Questions concerning some parts of the section on one-particle states in Weinberg's first volume on QFT clarity preface |
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1d |
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Questions concerning some parts of the section on one-particle states in Weinberg's first volume on QFT @LakshyaBhardwaj: Ah, now I see. Ouch, I did not recognize that interpretation of my words. The "slow student" in question is I, not you. Sorry for any offense; none was intended. I'll edit the post. |
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1d |
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Questions concerning some parts of the section on one-particle states in Weinberg's first volume on QFT @LakshyaBhardwaj: You're welcome (but no professors here). |
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May 15 |
awarded | Fanatic |
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May 13 |
revised |
Displacement Current - How to think of it? add a figure reference and improve the description (I hope) |
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May 13 |
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Displacement Current - How to think of it? @BenCrowell: Yes, it's an awkward description. See the 2nd figure in the Wikipedia article for displacement current: en.wikipedia.org/wiki/Displacement_current , where S1 and S2 are the 2 surfaces. |
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May 13 |
answered | Displacement Current - How to think of it? |
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May 6 |
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Definition of Casimir operator and its properties No problem, I was not expecting a proof, intuitive or otherwise. Your edit more than answered the mail and is much appreciated. |
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May 5 |
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Definition of Casimir operator and its properties @Vibert, thanks, but we are talking about "exact definitions". |
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May 5 |
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Definition of Casimir operator and its properties Nice, concise answer, as usual. (Personally, I'd like more explanation, but...) My venerable Schiff asserts that the number of Casimir invariants is equal to the maximum number of mutually commuting generators, which seems like a useful fact. Can you say how it emerges from your analysis (assuming it's true)? |
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May 5 |
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Definition of Casimir operator and its properties Since, as Qmechanic notes, Casimir operators need not be quadratic, it appears that the two definitions in the question are not in fact equivalent. |
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May 5 |
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Phasor representation of voltage in frequency domain @user1285419: You're welcome. Yes, $\beta x$ gives the phase characteristic of the wave as a function of position, but it has a fixed value of 0 at $x=0$. A complex amplitude permits that value to be different. |
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May 5 |
answered | Phasor representation of voltage in frequency domain |
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Apr 22 |
revised |
Faraday's law for a current loop being deformed added 817 characters in body |
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Apr 22 |
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Faraday's law for a current loop being deformed deleted 222 characters in body |
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Apr 22 |
revised |
Faraday's law for a current loop being deformed added 134 characters in body |
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Apr 22 |
answered | Faraday's law for a current loop being deformed |
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Apr 21 |
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Gravitational potential outside Lagrangian points or Lagrange points @AlanSE: just like the vector potential in electrodynamics, it turns out. See my answer to the question referenced in this question. |
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Apr 21 |
answered | Questions concerning some parts of the section on one-particle states in Weinberg's first volume on QFT |
