Ram Sidharth
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 Feb 2 awarded Notable Question Oct 7 awarded Notable Question Sep 22 awarded Famous Question Sep 21 awarded Popular Question Jun 19 awarded Popular Question Apr 8 awarded Notable Question Feb 10 awarded Notable Question Nov 11 awarded Popular Question Oct 15 awarded Popular Question Sep 24 awarded Autobiographer Sep 1 awarded Notable Question Aug 29 awarded Popular Question Jul 23 awarded Popular Question Jul 2 awarded Curious May 12 awarded Popular Question Feb 3 awarded Popular Question Jan 18 awarded Popular Question Sep 7 comment Gravitational force exerted by a rod on a point mass @udiboy. It is not on a site, it is from one of the coaching center study materials. The final answer comes out to be $F\ =\ \frac{Gm_1m_2}{r(L + r)}$. Is this what you would get if you solved the problem the right way? Sep 7 asked Gravitational force exerted by a rod on a point mass Aug 19 comment Work, Energy & Power - Body slides down a hemisphere Thank you very much for your answer. It has cleared a lot of doubts. But I have some questions. We know that $mgcos\theta \ =\ R_h$. $R_h$ becomes $0$ when $cos\theta$ becomes $0$. This would imply that the mass has slid all the way down to the foot of the hemisphere. But the answer that I get eventually is $h\ =\ \frac{2}{3}r$ which would mean it leaves the surface much before. The answer is contradictory, or maybe I'm interpreting this wrong. Could you clarify?