rudolph9
Reputation
Next privilege 250 Rep.
 Sep 13 awarded Popular Question Apr 30 awarded Notable Question Mar 17 awarded Popular Question Jan 17 awarded Popular Question Dec 3 awarded Constituent Dec 3 awarded Caucus Nov 16 awarded Critic Nov 1 awarded Famous Question Aug 28 awarded Notable Question Aug 4 accepted Constant Volume vs. Constant Pressure? Jul 28 accepted Computing the Poynting vector? Jul 28 awarded Commentator Jul 28 comment Computing the Poynting vector? It ended up being $S_z = -\frac{ c}{ \mu_0}(B_x^2 + B_y^2)$, a negative, and I do not understand why? How does the cross product work out... What I am I interpreting incorrect in the following: $\vec E = [c B_x, cB_y, 0], \vec B = [B_x, B_y, 0]$ and $\vec E \times \vec B = i(c B_y \cdot 0 - 0 \cdot B_y) - j(c B_x \cdot 0 - 0 \cdot B_x) + k(c B_x \cdot B_y - B_x \cdot B_y) = 0$ ? Jul 28 comment Computing the Poynting vector? How do I approach computing $E$, at $x = 0, y = 0, z = 0, t = 0$, wouldn't $B = B_x + B_y$, hence $E = c(B_x + B_y)$? (using this value doesn't give me the correct result) Jul 28 revised Computing the Poynting vector? added 2 characters in body Jul 28 asked Computing the Poynting vector? Jul 22 asked Constant Volume vs. Constant Pressure? Jul 22 comment Double internal energy, how much will the entropy change? Your answer definitely make way more sense! Jul 22 revised Double internal energy, how much will the entropy change? added 36 characters in body Jul 22 comment Double internal energy, how much will the entropy change? Also on the note of the $sigma$, the answer was given as $\sigma_{final} - \sigma_{initial} = 69.3$