# Sebastian Flückiger

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bio website location age member for 2 years, 2 months seen Aug 15 '12 at 12:31 profile views 22

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 Feb5 awarded Popular Question Nov7 awarded Notable Question Feb11 awarded Popular Question Jul22 awarded Scholar Jul22 accepted Degeneracy of Energy Levels for 2 identical particles in a One Dimensional box Jul20 awarded Supporter Jul20 comment Degeneracy of Energy Levels for 2 identical particles in a One Dimensional box thank you for this unbelievable thourough answer! it will take some time for me to process and understand it i will come back on it :) Jul20 comment Degeneracy of Energy Levels for 2 identical particles in a One Dimensional box thx for editing, altough: it is definitly NOT homework. its an exercise from an old exam. (at a certain point there is no such thing as 'homework' anymore) ;) Jul20 asked Degeneracy of Energy Levels for 2 identical particles in a One Dimensional box Feb1 comment change of resistance in semiconductors due to temperature change wheras conductivity and resistance indirectly proportional so it does not really matter which one you calculate =) if the resistance drops with a factor 3.5 the conductivity goes up by the same factor, and vice versa. Feb1 awarded Editor Feb1 revised change of resistance in semiconductors due to temperature change added 96 characters in body Feb1 awarded Teacher Feb1 answered change of resistance in semiconductors due to temperature change Feb1 comment change of resistance in semiconductors due to temperature change i couldnt because i had too little reputation. i will as soon as i get to a conputer (just cell here). rho is the specific resistance @akhmeteli Jan31 awarded Student Jan31 comment change of resistance in semiconductors due to temperature change haha thank you for this funny link :P as said - i was able to solve it myself =) Jan31 comment change of resistance in semiconductors due to temperature change i finally found the answer =) for anyone who is ineterested: $\rho(T)=\rho_0\cdot e^{-\frac{E_g}{2k_BT}}$ so the factor would be $\frac{\rho(Room)}{\rho(273.15)}=e^{-\frac{E_g}{2k_B300K}+\frac{E_g}{2k_B273.15K‌​}}$ to achieve 3,5 as factore we change the equation to find $E_g$ and get $E_g=-ln(3.5)\cdot 2k_B\cdot \frac{1}{\frac{1}{300K}-\frac{1}{273.15K}}\approx 0.65$ which is very close to 0.67, the bandgap of germanium. thanks for helping anyways =) Jan31 comment change of resistance in semiconductors due to temperature change oh yes clearly silicon (sry im swiss, in german its called 'silicium' confusing..) and yes it should be -aT but still i dont get to 3.5 onany, maybe iused the wrong a.. Jan31 comment change of resistance in semiconductors due to temperature change p = p_o * e^(a*T) but this gives factors of sizes up to 10^295 which is rediculous :/