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Oct
17
comment How can you determine the direction of the polarizing axis of a single polarizer?
Slightly pedantic but one could also use a pre-characterized light source which is linearly polarized in some intrinsic way. E.g., the laser gain in some anisotropic crystals can be polarization dependent.
Oct
16
revised Mirror that flips polarisation?
improved explanation and formatting
Oct
16
answered Mirror that flips polarisation?
Oct
12
revised What does $g^{(2)}$ signify in quantum optics? And how to calculate it?
corrected formula
Oct
11
comment Collinearity of two infrared (10.6um) beams
I would be inclined to say that the polarization may turn out to be okay if you use short fibers that are not subject to high environmental fluctuations, such as vibrations or temperature variations. Polarization controllers use birefringence and at least the basic principle should work. But it may require bending of the fiber which might add to your losses. So power budget might really be critical in the end.
Oct
11
revised What does $g^{(2)}$ signify in quantum optics? And how to calculate it?
added 130 characters in body
Oct
11
answered What does $g^{(2)}$ signify in quantum optics? And how to calculate it?
Oct
11
answered Collinearity of two infrared (10.6um) beams
Oct
9
awarded  Organizer
Oct
9
awarded  Commentator
Oct
7
comment What are the 'types' of parametric down conversion?
Good to know it helped. Perhaps you could mark this as an answer then?
Oct
6
answered What are the 'types' of parametric down conversion?
Oct
6
answered Why does Fermi level has a probability density of 1/2 while it may lie in the forbidden region?
Oct
6
comment Why does Dirac write $\langle\xi'|\overline{f(\xi)} = \overline f(\xi ')\langle\xi'|$?
I also agree with the answer of Nikos M. below. If you want to go further into deep & unchartered territories ;-), this link might be useful. As a gist, since $\xi$ is an observable, its eigenvalues $\xi^{'}$ must be real. In that case, its easy to see $\overline{f(\xi^{'})} = \overline{f}(\xi^{'})$
Sep
30
comment On solving a two lens system
Because the role played by the first lens together with the first (real) object has been completely taken into account. This one at a time procedure even holds for any complex optical assembly such as a cascade of $n$ lenses. The response of the $k^{th}$ lens in the cascade is influenced by lenses $1$ to $k-1$ but once we know this response, we can use that as an input to find the response of the $(k+1)^{th}$ lens while again ignoring all other lenses.
Sep
30
comment On solving a two lens system
At the end of the day, information is carried by the physical transmission of light. The notion of virtual images/objects mainly serves to ease the overall visualization of this flow while sign conventions allow the correct calculation of distances in each step. Also, the one at a time procedure holds for any complex assembly of lenses.
Sep
30
comment On solving a two lens system
Maybe one notion was not clarified: As you go from left to right, you consider one optical component at a time. That is to say, at $I_1$ when you consider that the real image produced by $L_1$ = virtual object for $L_2$, you can then forget $L_1$ completely.
Sep
30
answered On solving a two lens system
Sep
29
awarded  Yearling
Sep
26
comment Spontaneous parametric down conversion and relative time of emission of two entangled photons
The photons are emitted at the same time; see for instance journals.aps.org/prl/pdf/10.1103/PhysRevLett.25.84 You may also be aware of the Hong Ou Mandel experiment on two-photon interference using parametric down conversion. A much more comprehensive and detailed explanation of time resolution in two-photon interference experiments in general can be accessed at link.springer.com/article/10.1007%2Fs00340-003-1337-x which I would also recommend.