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Aug
27
reviewed Approve Is quantum indeterministic?
Aug
27
comment Branching lemon drop “smoke rings”
Awesome extension. Thanks!
Aug
26
reviewed Close Physics in Video Games
Aug
26
reviewed Close A curious case of Relativistic Velocity Addition
Aug
26
comment Branching lemon drop “smoke rings”
Well, the question is, how break up of the vortex rings into smaller vortex rings happens. At that point, you already lost the interface, so there is no surface tension. Right?
Aug
26
reviewed Leave Open Polchinski equation 4.3.16
Aug
26
reviewed Close Relationship of multiple particles under collision
Aug
26
reviewed Approve Why do we fall down when the bicycle slows down?
Aug
26
comment Branching lemon drop “smoke rings”
Can surface tension play a large role if the two fluids mix?
Aug
25
comment Branching lemon drop “smoke rings”
But I fail to see how the transition to turbulence is trigger. For smoke rings I see the point of buoyancy driven light/hot smoke hitting the stagnant cooled down smoke. But here I do not see something similar.
Aug
25
comment Branching lemon drop “smoke rings”
Did you estimate the Reynolds number? I would guess it is more of a laminar process, rather than turbulence.
Aug
25
awarded  Investor
Aug
25
reviewed Reopen Why do we fall down when the bicycle slows down?
Aug
25
comment Why do we fall down when the bicycle slows down?
The linked question reads "I could ask this on the physics site however I am hoping for a relatively simple answer."
Aug
25
comment Why do we fall down when the bicycle slows down?
See, e.g. rspa.royalsocietypublishing.org/content/463/2084/1955
Aug
25
comment Why do we fall down when the bicycle slows down?
Are you sure? I'm pretty sure I once saw a video with a counter-rotating wheel, such that the net angular momentum is zero. I think there are more effects playing a role
Aug
25
reviewed Approve How does bulk-boundary correspondence works for various cases of time-invariant system?
Aug
24
comment Dimensions of wave equation
@Rfield The dimension of $v$ does not matter, because it is on both sides. $\Delta=d^2/dx^2$ and $dx$ has dimension of meter, hence $[\lambda]=\text{m}^{-2}$.
Aug
24
reviewed Reject Can we use water as fuel for nuclear thermal space propulsion?
Aug
24
reviewed Approve My model of Conductors in “static” condition