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revised Does a random local unitary destroy entanglement
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Sep
12
comment Does a random local unitary destroy entanglement
Neat stuff! Thanks Martin. Still, what about my initial intuition. The state $\rho_A$, after the trace, is $0.5|0 \rangle + 0.5|1\rangle$. A random unitary on this would not change it. The VN entropy would not change.
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accepted Does a random local unitary destroy entanglement
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comment Does a random local unitary destroy entanglement
@SMKravec Hi, yes, by local, I mean applied to one qubit or another, or, as you wrote, a product of operators on the subsystems. So $U_A$ is local to $A$. Its not just a change of basis, however. I am considering the possibility of a random change of basis, for which there is absolutely no information for any observer.
Sep
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revised Does a random local unitary destroy entanglement
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Sep
12
comment Does a random local unitary destroy entanglement
@Martin, I guess, the idea is that if you can destroy a joint state by a random local, you are destroying it just by not knowing about something. However, I am thinking of density matrices which handle classical probabilities which can safely be seen as information based.
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revised Does a random local unitary destroy entanglement
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revised fixed input qubit state to an arbirary pure state using two variable rotations and one fixed rotation
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