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Mechanical Engineering Student at Georgia Tech

EMail:Gharrington44@gmail.com


2d
comment RMS Free Path vs Mean Free Path
@DavidZ I found an 8% difference between the two methods so I am not sure which one is more accurate
2d
comment RMS Free Path vs Mean Free Path
@DavidZ When you say the free path distribution is exponential in the book's derivation, are you referring to equation 3.68?
2d
comment RMS Free Path vs Mean Free Path
@DavidZ I found a resource that says $\Lambda_{rms}=\sqrt2 \Lambda$. It is found on page 180-181 of this book at this link and is equation 3.75... books.google.com/…
Apr
14
comment RMS Free Path vs Mean Free Path
@DavidZ Someone else told me the RMS free path is $\Lambda_{rms}=\sqrt2 \Lambda$
Apr
14
comment RMS Free Path vs Mean Free Path
@DavidZ, why do you tell me to not say $\Lambda=\bar v \tau$ but then you state that in your derivation? The same goes for $\Lambda_{rms}=\bar v_{rms} \tau_{rms}$
Apr
13
comment RMS Free Path vs Mean Free Path
I have no idea what to even do with that honestly. I am not a molecular physics guy. I just need to find a formula for RMS free path and there is nothing on google.
Apr
11
comment Molecular mean free path probability
I'm not really sure what kind of variable the $\xi$ is. It is just the distance the molecule will travel without a collision. I'm guessing it's continuous since it can be 0.01 or 0.012 or 0.013. Are you essentially saying that I should take "at least" and "greater than" to be the same?
Apr
4
comment Help with change in specific volume with time in piston cylinder?
WOW. I cannot believe I overlooked that mistake the entire time. Thanks a lot for the help. I also did it the way you mentioned in the endnote and I found it much more convenient
Apr
4
comment Help with change in specific volume with time in piston cylinder?
I used the quotient rule and obtained $$\frac{d}{dm}(\frac{V(m)}{m})=\frac{m\frac{dV}{dm}-V(m)\frac{d}{dm}(\frac{1}{m}‌​)}{m^2}=\frac{m\frac{dV}{dm}+\frac{1}{m^2}V}{m^2}$$ The only way I could think of expanding $\frac{dV}{dm}$ is by making it $\frac{dV}{dt}\frac{dt}{dm}$ or $\frac{d}{dm}(mv)=v\frac{dm}{dm}+m\frac{dv}{dm}$ which just puts me back to where I began
Apr
4
comment Help with change in specific volume with time in piston cylinder?
when I used the quotient rule I reached $$\frac{dv}{dm}=\frac{d}{dm}(\frac{V(m)}{m})=\frac{1}{m}\frac{dV}{dm}+\frac{1}{m‌​^4}V(m)$$ and right away I realized I must have done something wrong because I have an $m^4$ when I should. Also, won't $\frac{dV}{dm}=\frac{d}{dm}(mv)$ just get me back to $\frac{dv}{dm}$ which was square one?
Apr
4
comment Help with change in specific volume with time in piston cylinder?
when I used the quotient rule I reached $$\frac{dv}{dm}=\frac{d}{dm}(\frac{V(m)}{m})=\frac{1}{m}\frac{dV}{dm}+\frac{1}{m‌​^4}V(m)$$ and right away I realized I must have done something wrong because I have an $m^4$ when I should. Also, won't $\frac{dV}{dm}=\frac{d}{dm}(mv)$ just get me back to $\frac{dv}{dm}$ which was square one?
Mar
31
comment Which temperature to evaluate fluid properties in pipe?
I figured I could use the inlet temperature to find the inlet density and viscosity which would allow me to find the mass flow rate which I know is constant. I would then use the average temperature between inlet and outlet to find the nusselt number. I could then account for property variation from temperature change using $$Nu = Nu_{m}(\frac{\mu_{m}}{\mu_{s}})^{n}$$ Does this sound like a reasonable approach? Or do you think I should evaluate the inlet density at the average of the inlet and the surface temp?
Mar
11
comment Determine pipe outlet temperature without length?
@gregsan Are you sure there is no other way to find heat flux? This problem was on my professor's past exam and I am using it for practice. He must have made an error
Mar
3
comment Derivation of cylindrical line heat source problem?
Unfortunately I do have to do it this way. I agree that SoV and Bessel functions would be much easier
Feb
3
comment What does the absence of hydrodynamic entrance effects do to the momentum conservation Equation?
Even though the flow is still developing? I know there is velocity in the radial direction while the flow is still developing so I figured there would also be velocity in the theta direction
Feb
3
comment What does the absence of hydrodynamic entrance effects do to the momentum conservation Equation?
this is awesome. Thank you. I have one more question. Assuming an axi-symmetric pipe, is there a fluid velocity in the theta direction when the flow is still developing? My professor said in an email that there is no fluid velocity in the theta direction when the flow is still developing but I don't see why this is. If there is no velocity in the theta direction when it is developing or when it is fully developed then is there ever a fluid velocity in the theta direction?
Jan
30
comment What does the absence of hydrodynamic entrance effects do to the momentum conservation Equation?
Also, Someone just tried to tell me that even thought the flow velocity profile does not change with time or space, the magnitude of the velocity does change
Jan
30
comment What does the absence of hydrodynamic entrance effects do to the momentum conservation Equation?
@Bernhard, I assuming you are hinting towards the fact velocity profile does not change with time or space. Am I right?
Sep
9
comment Which pressure to use in the $T~ds$ equation?
We have never learned about $\mu dN$ in class and there is no outlet in the specified problem
Sep
8
comment Shouldn't the sign of generated entropy always be positive?
I changed the temperature to Kelvin in the natural log arguments so hopefully it is correct now