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seen Apr 15 at 4:32

Mechanical Engineering Student at Georgia Tech

EMail:Gharrington44@gmail.com


Apr
15
comment RMS Free Path vs Mean Free Path
@DavidZ I found an 8% difference between the two methods so I am not sure which one is more accurate
Apr
15
comment RMS Free Path vs Mean Free Path
@DavidZ When you say the free path distribution is exponential in the book's derivation, are you referring to equation 3.68?
Apr
15
comment RMS Free Path vs Mean Free Path
@DavidZ I found a resource that says $\Lambda_{rms}=\sqrt2 \Lambda$. It is found on page 180-181 of this book at this link and is equation 3.75... books.google.com/…
Apr
14
asked How do I determine resistivity from electron defects of high purity gold?
Apr
14
comment RMS Free Path vs Mean Free Path
@DavidZ Someone else told me the RMS free path is $\Lambda_{rms}=\sqrt2 \Lambda$
Apr
14
comment RMS Free Path vs Mean Free Path
@DavidZ, why do you tell me to not say $\Lambda=\bar v \tau$ but then you state that in your derivation? The same goes for $\Lambda_{rms}=\bar v_{rms} \tau_{rms}$
Apr
14
accepted RMS Free Path vs Mean Free Path
Apr
13
comment RMS Free Path vs Mean Free Path
I have no idea what to even do with that honestly. I am not a molecular physics guy. I just need to find a formula for RMS free path and there is nothing on google.
Apr
13
asked RMS Free Path vs Mean Free Path
Apr
12
asked Do I ever not account for temperature variation from wall temperature in pipe flow?
Apr
11
comment Molecular mean free path probability
I'm not really sure what kind of variable the $\xi$ is. It is just the distance the molecule will travel without a collision. I'm guessing it's continuous since it can be 0.01 or 0.012 or 0.013. Are you essentially saying that I should take "at least" and "greater than" to be the same?
Apr
11
asked Molecular mean free path probability
Apr
8
asked Is my method of calculating thermal conductivity of a metal wrong?
Apr
4
awarded  Popular Question
Apr
4
accepted Help with change in specific volume with time in piston cylinder?
Apr
4
comment Help with change in specific volume with time in piston cylinder?
WOW. I cannot believe I overlooked that mistake the entire time. Thanks a lot for the help. I also did it the way you mentioned in the endnote and I found it much more convenient
Apr
4
comment Help with change in specific volume with time in piston cylinder?
I used the quotient rule and obtained $$\frac{d}{dm}(\frac{V(m)}{m})=\frac{m\frac{dV}{dm}-V(m)\frac{d}{dm}(\frac{1}{m}‌​)}{m^2}=\frac{m\frac{dV}{dm}+\frac{1}{m^2}V}{m^2}$$ The only way I could think of expanding $\frac{dV}{dm}$ is by making it $\frac{dV}{dt}\frac{dt}{dm}$ or $\frac{d}{dm}(mv)=v\frac{dm}{dm}+m\frac{dv}{dm}$ which just puts me back to where I began
Apr
4
comment Help with change in specific volume with time in piston cylinder?
when I used the quotient rule I reached $$\frac{dv}{dm}=\frac{d}{dm}(\frac{V(m)}{m})=\frac{1}{m}\frac{dV}{dm}+\frac{1}{m‌​^4}V(m)$$ and right away I realized I must have done something wrong because I have an $m^4$ when I should. Also, won't $\frac{dV}{dm}=\frac{d}{dm}(mv)$ just get me back to $\frac{dv}{dm}$ which was square one?
Apr
4
comment Help with change in specific volume with time in piston cylinder?
when I used the quotient rule I reached $$\frac{dv}{dm}=\frac{d}{dm}(\frac{V(m)}{m})=\frac{1}{m}\frac{dV}{dm}+\frac{1}{m‌​^4}V(m)$$ and right away I realized I must have done something wrong because I have an $m^4$ when I should. Also, won't $\frac{dV}{dm}=\frac{d}{dm}(mv)$ just get me back to $\frac{dv}{dm}$ which was square one?
Apr
4
asked Help with change in specific volume with time in piston cylinder?