meta user
network profile
| bio | website | |
|---|---|---|
| location | Spain | |
| age | 26 | |
| visits | member for | 1 year, 7 months |
| seen | 18 hours ago | |
| stats | profile views | 122 |
Undergraduate physics student at Spain.
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22h |
reviewed | No Action Needed Widom-Larsen Theory |
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22h |
reviewed | No Action Needed Periodic boundary condition on a Wave Function of a Particle in a Box |
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22h |
suggested | suggested edit on Periodic boundary condition on a Wave Function of a Particle in a Box |
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23h |
reviewed | No Action Needed How to calculate beam spread of a non-point light source via an aspheric lens |
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23h |
awarded | Critic |
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23h |
reviewed | Reviewed How a spacecraft travelling near light speed avoid asteroids? |
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2d |
comment |
Optical depth in astrophysics Understood, thank you very much! |
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2d |
comment |
Optical depth in astrophysics Hi Christ, thanks. I'm still stuck seeing why your first ODE holds. The following steps are cristal clear. |
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2d |
asked | Optical depth in astrophysics |
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May 1 |
answered | Ricci tensor for a 3-sphere without Math packets |
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Mar 28 |
comment |
How to solve following equation (Yukawa field)? Probably Green function for the homogeneous equation is the way to go, then plug in your $j^{\alpha}$ |
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Mar 25 |
comment |
N-electron system ground state Yes, in this level of calculation your energy depends on $k^2$ and $k^2$ only, as you can see in the $E_{k}$ explicit expression |
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Mar 25 |
answered | N-electron system ground state |
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Mar 22 |
accepted | Product of exponential of operators |
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Mar 20 |
accepted | Annihilation and creation operator - $\phi$ and $\pi$ for Klein-Gordon Field |
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Mar 20 |
asked | Product of exponential of operators |
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Mar 20 |
comment |
Find $x$ operator given $p$ @JKL No, it is not give but it should be something like $[x,A+B]=Ci\hbar$ for some $C$ |
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Mar 20 |
accepted | Weinberg's proof that Levi-Civita Symbol is a tensor |
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Mar 19 |
comment |
Weinberg's proof that Levi-Civita Symbol is a tensor Hi, thanks. I'm sorry but I still don't get it.. when I switch $\epsilon$ and $\zeta$ in the Levi-Civita symbol I add a minus sign, and the indices in the Lorentz transformation should be switched too. Then how I relabel the dummy indices? switching back $\zeta$ to $\epsilon$? |
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Mar 19 |
asked | Weinberg's proof that Levi-Civita Symbol is a tensor |
