# experimentX

less info
reputation
316
bio website location age member for 3 years seen Dec 6 at 15:26 profile views 124

:(

# 117 Actions

 Dec5 awarded Popular Question Nov30 awarded Excavator Nov30 revised Galilean transformation of wave equation fixed latex Nov30 comment Galilean transformation of wave equation Hi ... shouldn't $\frac{\partial }{\partial x'} = \frac{\partial }{\partial x} - \frac{1}{V}\frac{\partial }{\partial t}$?? could you elaborate why just $\frac{\partial}{\partial x} = \frac{\partial}{\partial x'}$ ?? Nov30 suggested suggested edit on Galilean transformation of wave equation Oct31 awarded Notable Question Oct22 awarded Popular Question Sep9 comment Investigation of a pendulum's period, problem creating equation to sum the dynamic velocity the $t=t(\theta)$ is itself an approximating function. Naturally i would expect and approximating function. Seems that it exists from equation $(31)$ in that paper. (+1) Sep9 comment Investigation of a pendulum's period, problem creating equation to sum the dynamic velocity i would like to know if inverse of this function $t = t(\theta)$ exist or not. Apr30 awarded Popular Question Mar19 awarded Popular Question Jan14 awarded Popular Question Sep21 awarded Custodian Aug17 answered First integral of an equation of motion: $\mu\ddot r=-\frac{k}{r^2}$ Aug6 comment Why do rolling disc (coin) move in circular path? all right thanks!! Aug6 accepted Why do rolling disc (coin) move in circular path? Aug6 revised Why do rolling disc (coin) move in circular path? added 109 characters in body Aug6 comment Why do rolling disc (coin) move in circular path? @Ankush The coin is moving in circle means it should be spinning ... with period equal to the period of circular motion. Aug6 comment Why do rolling disc (coin) move in circular path? $J$ is angular momentum. Aug6 comment Why do rolling disc (coin) move in circular path? @Ankush since the coin is moving in circle ... something must continuously change the direction of the coin (so that coin follows circular path).