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dr dr dr! im cia he wasnt alone uh you dont get to bring friends theyre not my friends dont worry no charge for them and why would i want them they were trying to grab your prize they work for the mercenary the masketta man bane aye get them on board ill call ittin the flight plan i just filed with the agency lists smee maimen doctor pavelheer button lee juan ovyu first one to talk gets to stay on my aircraft who paid you to grab dr pavel he didnt fly so good who wants to try next tell me about bane why does he wear the mask a lotta loyalty for a hired gun or perhaps he's wondering why someone would shoot a man before throwing him out of a plane at least you can talk who are you it doesnt matter who we are what matters is our plan if i pull that off will you die it would be extremely painful youre a big guy for you was getting caught part of your plan of course dr pavel refused our offer in favor of yours we had to find out what he told you nothing i said nothing well congratulations you got yourself caught sir now whats the next step of your master plan crashing this plane with no survivors no they expect one of us in the wreckage brother have we started the fire yes the fire rises calm down doctor nows not the time for fear that comes later


Aug
25
awarded  Nice Question
Aug
19
comment Kinetic energy as $\pi k_B T$
@LubošMotl: The question is if it matters as long as you keep on using a temperature-unit that's formally distinct from an energy unit. Sure, you may take the reductionist approach and fix all factors using the deeper theory, but "I haven't seen what the energy (...) is converted into" and so if all quantities in the theories account for this strange $\pi$, it may end up not ruining any results. I agree that it's odd that a particle should carry an irrational energy-quantity - I'm not advocating it. But apparently people have used this quantity for some time and it worked for their use.
Aug
19
comment Kinetic energy as $\pi k_B T$
@LubošMotl: You don't need to violate any exact entropy expressions or the absolute temperature scale. Just consider $k_B^*\equiv \pi\,k_B$ the auxiliary constant. Some like $k_B=1$ and electron volts, and some might find $\approx 10^{-23}J/K$ and kelvins or "pi-kelvins" useful. That's why I said I don't know what would be the merit of adopting another $3.14$ to get energy out of temperature. I showed OP where $\sqrt{\pi}$ pops up. In expectation values, it will pop out anyway, because the density $\rho\propto{\mathrm e}^{-H\,/\,k_BT}$ gets normalized.
Aug
19
revised Kinetic energy as $\pi k_B T$
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Aug
19
revised Kinetic energy as $\pi k_B T$
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Aug
19
answered Kinetic energy as $\pi k_B T$
Aug
19
revised How to compute this change of Gibbs energy for a Van der Waals gas?
added 631 characters in body
Aug
17
comment Isothermal versus Isometric/Isochoric
You can make a big delta $\Delta$ via backslash Delta. Also, are you sure it "literally means zero temperature change"? 'zero' in Latin would be a word starting with 'n'.
Aug
17
comment Third principle of Nernst
@Qmechanic: The duplicate has been deleted.
Aug
16
comment How to compute this change of Gibbs energy for a Van der Waals gas?
@Gert: I'm not sure which aspect of your question isn't answered by the first sentence.
Aug
16
asked How to compute this change of Gibbs energy for a Van der Waals gas?
Aug
14
awarded  Favorite Question
Aug
14
comment Configurations and configuration manifold in Lagrangian Optics
To what extent are you aware of variational principles in simple geometry, energy functionals, etc. I'm not sure if here you want to make sense of the notion "configuration" for a theory without dynamics, just for the sake of it.
Aug
10
comment Why $C_{abcd}C^{abcd}$ in de Sitter–Schwarzschild metric doesn't depend on $\Lambda$
@user34669: I'm not sure if this is intended as a response to what I propose, is it?
Aug
10
comment Why $C_{abcd}C^{abcd}$ in de Sitter–Schwarzschild metric doesn't depend on $\Lambda$
It would be interesting take $-f(r)\,\mathrm dt^2+\frac{1}{f(r)}\mathrm d r^2+r^2\mathrm d\theta+r^2\sin^2\theta\,\mathrm d\theta \mathrm \,d\phi$, compute the scalar, set it to $c\,r^n$ and solve the ODE. Challenge accepted?
Aug
5
awarded  Popular Question
Aug
2
comment What are the technical obstructions that prevent scale relativity from being a viable theory of quantum-gravity?
I have the feeling that hardly anybody knows of the theory (which in part is an answer to the question too). Like with Fractional anything, if no big solution to an old problem through it is being made popular and/or if the author isn't popular, getting ideas known is very hard. Nobody's who isn't payed for it is gonna invest the time to look into it in the first place - to take the time must presuppose a suspicion you can get something out of it. There are also tools like Gyrovector spaces nobody uses for SRT, and so on and so on.
Aug
1
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Jul
22
awarded  Popular Question
Jul
14
awarded  Notable Question