network profile
| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 1 year, 10 months |
| seen | Sep 22 '12 at 10:55 | |
| stats | profile views | 39 |
An undergraduate student major in mathematics.
|
Oct 9 |
awarded | Popular Question |
|
Sep 21 |
awarded | Custodian |
|
Feb 25 |
comment |
Uncertainty Principle for a Totally Localized Particle But what about a macroscopic object(and that is why I'm confused)? For example, a stone. Common sense would tell us it can be totally localized and momentum be zero. Is it because the Planck constant is too small so we cannot observe the spreading? |
|
Feb 25 |
accepted | Uncertainty Principle for a Totally Localized Particle |
|
Feb 24 |
awarded | Nice Question |
|
Feb 24 |
asked | Uncertainty Principle for a Totally Localized Particle |
|
Aug 19 |
comment |
About the energy with the repulsive potential Thanks, but how to see there is no solution for $E=0$ more clearly? Actually I have thought that my numerical solution tends to a solution with $E=0$. |
|
Aug 19 |
accepted | About the energy with the repulsive potential |
|
Aug 19 |
comment |
About the energy with the repulsive potential I think your answer is clear and convincing. And two more questions(maybe silly), does "all $E$ are allowed" imply that $E$ can be very large(even larger than $mc^2$)? And as my numerical result shows that $E$ tends to $0$ when I try to find a bound state, is it correct to say that bound state exists for $E=0$? |
|
Aug 19 |
comment |
About the energy with the repulsive potential I'm interested in the "ground state", if it exists. My numerical procedure tries to find the minimum energy. |
|
Aug 19 |
revised |
About the energy with the repulsive potential added 62 characters in body |
|
Aug 19 |
asked | About the energy with the repulsive potential |
|
Jul 30 |
comment |
Radial Schrodinger equation with inverse power law potential I just read this paper: sciencedirect.com/science/article/pii/037596019191081N How do you think of this paper? |
|
Jul 30 |
comment |
Radial Schrodinger equation with inverse power law potential My experiment shows that when $\beta$ tends to $2$ from below, the solution tends to singular(like a delta function) and the ground state energy tends to $-\infty$. |
|
Jul 30 |
comment |
Solving one dimensional Schrodinger equation with finite difference method How to change the variable for the spatial coordinate properly in this case? I have tried $r\to t:\exp(Kt)=1+Kr$, but the numerical solution seems to be more unstable. |
|
Jul 30 |
accepted | Solving one dimensional Schrodinger equation with finite difference method |
|
Jul 29 |
accepted | Radial Schrodinger equation with inverse power law potential |
|
Jul 29 |
comment |
Radial Schrodinger equation with inverse power law potential Thanks for your advice, it's really a brilliant idea. |
|
Jul 29 |
revised |
Radial Schrodinger equation with inverse power law potential edited body |
|
Jul 28 |
comment |
Radial Schrodinger equation with inverse power law potential That is what I mean. For the hydrogen atom, $\alpha<0,\beta=1$, and unbound solutions exist for certain discrete $E<0$. So I guess that it remains true for $\alpha<0,\beta=2$, but when I tried to find $E<0$ numerically, the result turns out that the minimum $E$ tends to $-\infty$, and higher $E$(still $E<0$) are not of certain discrete choices. |
