meta user
network profile
| bio | website | flavors.me/jdyearsley |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 1 year, 11 months |
| seen | Jul 30 '12 at 2:03 | |
| stats | profile views | 14 |
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Mar 20 |
comment |
How is contact resistivity defined for a Schottky contact, or the Schottky barrier height for an ohmic contact? Thank you! This is exactly what I was looking for. Is the reason why the IV curve linearizes due to the fact that after a certain forward bias, a very large proportion of the carriers will be at an energy greater or equal to the SBH, and any additional bias doesn't largely change the ability for carriers to emit over the barrier, but rather just changes the velocity? Also, when you say very-forward-bias are you referring to greater or equal bias to achieve flat band conditions in the semiconductor? |
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Mar 20 |
accepted | How is contact resistivity defined for a Schottky contact, or the Schottky barrier height for an ohmic contact? |
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Mar 19 |
revised |
How is contact resistivity defined for a Schottky contact, or the Schottky barrier height for an ohmic contact? A little more explanation of 2nd part of the question. |
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Mar 19 |
asked | How is contact resistivity defined for a Schottky contact, or the Schottky barrier height for an ohmic contact? |
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Feb 24 |
comment |
Can surface dipoles/charges change the work function of a metal? Thanks for the explanation. I was wondering, why is the top of the conduction band of the metal never ever shown? I have not seen one diagram where it is drawn. Is there a physical reason for this? |
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Feb 24 |
accepted | Can surface dipoles/charges change the work function of a metal? |
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Feb 24 |
comment |
Can surface dipoles/charges change the work function of a metal? Sure, here you go: iue.tuwien.ac.at/phd/ayalew/img308.png |
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Feb 22 |
asked | Can surface dipoles/charges change the work function of a metal? |
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Sep 28 |
accepted | How does thermal broadening of the Fermi Function cause electron coherence loss? |
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Sep 27 |
comment |
How does thermal broadening of the Fermi Function cause electron coherence loss? The coherence calculation this is used for is the thermal diffusion length. $$L_T=\sqrt{D\tau_T}=\sqrt{\frac{Dh}{k_BT}}$$ At distances (or device dimensions being inspected) become longer than the thermal diffusion length, the electrons in the system can no longer be considered coherent. |
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Sep 26 |
awarded | Editor |
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Sep 26 |
revised |
How does thermal broadening of the Fermi Function cause electron coherence loss? deleted 2 characters in body |
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Sep 26 |
asked | How does thermal broadening of the Fermi Function cause electron coherence loss? |
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Sep 17 |
comment |
Why does the density of states in a solid scale as $\sqrt{E}$? Does this relationship hold for atypical band k-space shapes like graphene (linear, forming cones in 3d)? In other words, would the DoS for graphene in 3 dimensions scale as $E^2$, since $\alpha=1$? |
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Sep 17 |
awarded | Supporter |
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Sep 17 |
accepted | Why does the density of states in a solid scale as $\sqrt{E}$? |
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Sep 15 |
awarded | Student |
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Sep 15 |
asked | Why does the density of states in a solid scale as $\sqrt{E}$? |
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Aug 30 |
awarded | Scholar |
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Aug 30 |
accepted | References for the source and application of bonding-antibonding splitting on electronic structure? |
