Juan Sebastian Totero

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212 reputation
18
bio website jstotero.com
location Rome, Italy
age 27
visits member for 3 years, 2 months
seen Jun 23 at 10:15

Jan
14
comment Interpretation of the Random Schrödinger Equation
@RonMaimon:Thx for your reference, I already studied the original paper from Parisi and Sourlas, and reviewed the supersymmetric approach to stochastic problems on Zinn-Justin's book, and some Gozzi's papers. I'll take a look at Oz's article :)
Dec
12
awarded  Critic
Dec
10
comment Gaussian Integrals : Functional determinant expressed as a trace
@Qmechanic : can you suggest me some reference about the trace regularization?
Dec
9
awarded  Yearling
Dec
9
comment A certain $\cal{N}=2$ superconformal theory (or is it?)
Great insight :) Thanks
Dec
9
comment Interpretation of the Random Schrödinger Equation
@Ron Maimon : Actually this is a very interesting answer. Could you provide me some references about the supersymmetric approach to obtain mean quantities? I am currently studying a random electromagnetic system, and after attacking it with the replica-trick, I'm willing to try the more rigorous SUSY formulation, but I cannot find more detalied information on it.
Dec
9
answered What is replica symmetry breaking, and what is a good resource for learning it?
Dec
9
revised Gaussian Integrals : Functional determinant expressed as a trace
changed title, clarifications
Dec
9
revised Gaussian Integrals : Functional determinant expressed as a trace
changed title, clarifications
Dec
8
comment Gaussian Integrals : Functional determinant expressed as a trace
@Vibert : Actualy expanding the $\log$ was my idea. Provided idk how to manage an expansion over "abstract operators", I would like to project the whole $\mathrm{Tr} \log [..]$ over $x$ or $k$, and then expand the projected logarithm. But how exactly does a $\mathrm{Tr}$ projection work?
Dec
8
revised Gaussian Integrals : Functional determinant expressed as a trace
added 38 characters in body
Dec
8
revised Gaussian Integrals : Functional determinant expressed as a trace
deleted 5 characters in body
Dec
8
comment Gaussian Integrals : Functional determinant expressed as a trace
Symmetric matrix, sorry, I wrote it wrong. In the full calculation I have to do, $\varphi$ is a real field and $\psi$ is a grassman-odd variable.
Dec
8
revised Gaussian Integrals : Functional determinant expressed as a trace
added 4 characters in body
Dec
8
awarded  Disciplined
Dec
8
asked Gaussian Integrals : Functional determinant expressed as a trace
Dec
8
awarded  Teacher
Nov
5
accepted Quantum Field Theory: why fields are equal to zero on the boundary?
Nov
5
accepted Field theory:functional derivative involving Fourier Transform
Nov
5
comment Field theory:functional derivative involving Fourier Transform
Yes I know you can do it by glance, but I did every step just to be sure something pedantic was not happening here :). The next step in my work here was to integrate the above derivative, notice it is just an inverse fourier transform (due to the supposed positive exponent), and then use the convolution theorem to move back to the real space. Actually, this is not a real problem because I found a much faster solution that avoids me this calculation and produces me the right result in zero time :) Thx, I'll set your answer as right, given it's a good example of a direct calculation :)