network profile
| bio | website | jstotero.com |
|---|---|---|
| location | Rome, Italy | |
| age | 26 | |
| visits | member for | 1 year, 11 months |
| seen | May 8 at 13:23 | |
| stats | profile views | 37 |
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Jan 14 |
comment |
Interpretation of the Random Schrödinger Equation @RonMaimon:Thx for your reference, I already studied the original paper from Parisi and Sourlas, and reviewed the supersymmetric approach to stochastic problems on Zinn-Justin's book, and some Gozzi's papers. I'll take a look at Oz's article :) |
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Dec 12 |
awarded | Critic |
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Dec 10 |
comment |
Gaussian Integrals : Functional determinant expressed as a trace @Qmechanic : can you suggest me some reference about the trace regularization? |
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Dec 9 |
awarded | Yearling |
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Dec 9 |
comment |
A certain $\cal{N}=2$ superconformal theory (or is it?) Great insight :) Thanks |
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Dec 9 |
comment |
Interpretation of the Random Schrödinger Equation @Ron Maimon : Actually this is a very interesting answer. Could you provide me some references about the supersymmetric approach to obtain mean quantities? I am currently studying a random electromagnetic system, and after attacking it with the replica-trick, I'm willing to try the more rigorous SUSY formulation, but I cannot find more detalied information on it. |
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Dec 9 |
answered | What is replica symmetry breaking, and what is a good resource for learning it? |
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Dec 9 |
revised |
Gaussian Integrals : Functional determinant expressed as a trace changed title, clarifications |
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Dec 9 |
revised |
Gaussian Integrals : Functional determinant expressed as a trace changed title, clarifications |
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Dec 8 |
comment |
Gaussian Integrals : Functional determinant expressed as a trace @Vibert : Actualy expanding the $\log$ was my idea. Provided idk how to manage an expansion over "abstract operators", I would like to project the whole $\mathrm{Tr} \log [..]$ over $x$ or $k$, and then expand the projected logarithm. But how exactly does a $\mathrm{Tr}$ projection work? |
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Dec 8 |
revised |
Gaussian Integrals : Functional determinant expressed as a trace added 38 characters in body |
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Dec 8 |
revised |
Gaussian Integrals : Functional determinant expressed as a trace deleted 5 characters in body |
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Dec 8 |
comment |
Gaussian Integrals : Functional determinant expressed as a trace Symmetric matrix, sorry, I wrote it wrong. In the full calculation I have to do, $\varphi$ is a real field and $\psi$ is a grassman-odd variable. |
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Dec 8 |
revised |
Gaussian Integrals : Functional determinant expressed as a trace added 4 characters in body |
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Dec 8 |
awarded | Disciplined |
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Dec 8 |
asked | Gaussian Integrals : Functional determinant expressed as a trace |
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Dec 8 |
awarded | Teacher |
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Nov 5 |
accepted | Quantum Field Theory: why fields are equal to zero on the boundary? |
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Nov 5 |
accepted | Field theory:functional derivative involving Fourier Transform |
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Nov 5 |
comment |
Field theory:functional derivative involving Fourier Transform Yes I know you can do it by glance, but I did every step just to be sure something pedantic was not happening here :). The next step in my work here was to integrate the above derivative, notice it is just an inverse fourier transform (due to the supposed positive exponent), and then use the convolution theorem to move back to the real space. Actually, this is not a real problem because I found a much faster solution that avoids me this calculation and produces me the right result in zero time :) Thx, I'll set your answer as right, given it's a good example of a direct calculation :) |
