| bio | website | |
|---|---|---|
| location | United States | |
| age | ||
| visits | member for | 2 years, 6 months |
| seen | 8 hours ago | |
| stats | profile views | 303 |
Started programming on a ZX spectrum in the 80's and have moved through Assembly, Turbo Pascal, C++, C#, Fortran. My main area of focus is engineering and scientific computing like numerical methods and 3D graphics.
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May 2 |
answered | How to determine a reaction force? |
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Apr 30 |
awarded | Custodian |
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Apr 30 |
reviewed | Reopen When can a body of water glow in space? |
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Apr 30 |
reviewed | Reviewed Where do high-energy neutrinos come from? |
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Apr 30 |
reviewed | Leave Open Finding the work required to move an object under pressure without knowing volume |
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Apr 30 |
awarded | Custodian |
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Apr 29 |
answered | Acceleration in the rate of expanansion of the universe due to weakening gravity? |
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Apr 29 |
comment |
Double Compound Pendulum: why use inertia about the center of mass for bottom pendulum? By definition kinetic energy is summed at the CM because that is where one expresses Newton's & Euler's laws of motion. |
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Apr 29 |
comment |
Double Compound Pendulum: why use inertia about the center of mass for bottom pendulum? Yes, CG is center of gravity, or center or mass CM. |
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Apr 29 |
revised |
How does the resistance force on a rolling ball depend on the ball radius? added 54 characters in body |
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Apr 29 |
answered | Double Compound Pendulum: why use inertia about the center of mass for bottom pendulum? |
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Apr 26 |
revised |
Rotational Dynamics added 60 characters in body |
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Apr 25 |
comment |
Nonuniform acceleration due to rubber rope The answer is that if $F(x)$ is your function then the acceleration is $\ddot{x} = \mbox{-} \frac{F(x)}{m} = \mbox{-} A x^b $ with the initial conditions $t=0$, $x=x_0$, $v=0$ where $x_0$ is the initial extension. |
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Apr 25 |
answered | interpreting aspects of rotational motion conceptually |
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Apr 25 |
comment |
Period of oscilation Have you tried anything? Can you show us at least a force balance or some effort to get an answer? |
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Apr 25 |
comment |
Nonuniform acceleration due to rubber rope @JJFleck - If $x$ is extension the above is correct. If $x$ is position then acceleration is $a=A\,(-x)^b$ but with $x<0$. If you shoot to the right (positive direction), the you move the payload to the left (negative direction) to stretch the rope. Either way the math is the same, and only the initial conditions change. |
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Apr 25 |
comment |
Nonuniform acceleration due to rubber rope Hmm, it depends on what the x-axis of the graph represents. Is it position or extension? Let me check again. |
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Apr 25 |
comment |
What Physical Quantity has SI Unit $kg \cdot m$,? Sometimes torque is specified in kilogram-meter meaning the weight of 1 kilogram mass at one meter lever. Assumes standard gravity of $g=9.80665 \rm m/s^2$ |
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Apr 25 |
revised |
Change of variables in an interval expression added 6 characters in body |
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Apr 25 |
comment |
Nonuniform acceleration due to rubber rope With the acceleration he has of the form $a=A x^b$ when you start numerically have to take care of the initial $x=0$ condition, where you are left with zero acceleration and nothing moves. You need an implicit integration scheme for this to work right. |