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| bio | website | cambridge.academia.edu/… |
|---|---|---|
| location | Cambridge, United Kingdom | |
| age | 23 | |
| visits | member for | 2 years |
| seen | 7 hours ago | |
| stats | profile views | 660 |
Currently undertaking Part III of the Mathematical Tripos at the University of Cambridge.
Previously obtained a B.S. in Mathematics and a B.A. in Physics from the University of Chicago (2012).
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Dec 5 |
comment |
Why quantum mechanics? See edit to question. Obviously, you'e going to have to appeal to experiment somewhere, but I feel as if the less we have to reference experiment, the more eloquent the answer would be. |
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Dec 5 |
revised |
Why quantum mechanics? added 427 characters in body |
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Dec 5 |
comment |
Why quantum mechanics? As an example of motivation that would satisfy me, the arguments that Weinberg makes in the first part of his first volume to motivate the introduction of quantum fields, while not a proof that nature has to be explained by a field theory, is more than satisfactory if all one seeks is justification to believe that a quantum field theory can be used to describe the universe. |
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Dec 5 |
asked | Why quantum mechanics? |
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Dec 5 |
awarded | Constituent |
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Dec 5 |
awarded | Caucus |
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Nov 8 |
accepted | What is the role of the vacuum expectation value in symmetry breaking and the generation of mass? |
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Nov 8 |
comment |
What is the role of the vacuum expectation value in symmetry breaking and the generation of mass? I don't quite see how the requirement that you not have a linear term requires us to make the substitution $\psi :=\phi -|v|$. For example, the trivial substitution $\psi := \phi$ doesn't have a linear term, but this can't be correct, because we don't see a massless particle and antiparticle pair, we see a Goldstone boson and a massive real scalar particle. |
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Nov 8 |
asked | What is the role of the vacuum expectation value in symmetry breaking and the generation of mass? |
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Oct 30 |
comment |
Is the density operator a mathematical convenience or a 'fundamental' aspect of quantum mechanics? Perhaps I could rephrase my question as "Does there exist a quantum system that exists in reality which cannot be mathematically described by a pure state?". According to your answer, it seems that the answer is "Yes" and that an example is given by "open quantum systems". What exactly do you mean by this and how are they not described by pure states? |
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Oct 30 |
comment |
Is the density operator a mathematical convenience or a 'fundamental' aspect of quantum mechanics? @A.O.Tell Can you elaborate on what exactly you mean by "representing states of tensor factor subsystems"? |
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Oct 30 |
asked | Is the density operator a mathematical convenience or a 'fundamental' aspect of quantum mechanics? |
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Oct 18 |
awarded | Notable Question |
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Oct 4 |
accepted | Why Negative Energy States are Bad |
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Oct 4 |
answered | Why Negative Energy States are Bad |
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Sep 8 |
awarded | Popular Question |
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Jul 27 |
awarded | Nice Question |
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May 31 |
asked | Lepton Number Conservation |
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May 30 |
comment |
Yukawa Coupling of a Scalar $SU(2)$ Triplet to a Left-Handed Fermionic $SU(2)$ Doublet This part of my question can be phrased as: given this statement of the problem, what is the correct form of the Yukawa coupling term? (I realize what I wrote down didn't make sense. The problem is, I don't know how to modify it so that it does make sense). |
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May 30 |
comment |
Yukawa Coupling of a Scalar $SU(2)$ Triplet to a Left-Handed Fermionic $SU(2)$ Doublet This actually came from a homework problem (there was a five tag limit). The problem reads: "One method of generating neutrino masses that we did not discuss in class involves adding a Higgs field $T$ which is a triplet under $SU(2)_L$ with a Yukawa coupling to the left-handed lepton doublets. If this triplet is a complex field, then it is possible to assign a lepton number to this new scalar field such that the lepton number is conserved.". He doesn't actually write out the Yukawa coupling term, so we are left to figure this out on our own. |
