| bio | website | |
|---|---|---|
| location | Russia | |
| age | ||
| visits | member for | 2 years |
| seen | May 5 '12 at 20:03 | |
| stats | profile views | 234 |
Scientist
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Apr 30 |
awarded | Yearling |
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May 4 |
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Information conservation during quantum measurement in $\psi$-epistemic interpretations May be interesting: mathoverflow.net/questions/95537/… |
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Apr 30 |
awarded | Yearling |
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Apr 4 |
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Negative probabilities in quantum physics Feynman wrote in this essay: "Trying to think of negative probabilities gave me a cultural shock at first, but when I finally got easy with the concept I wrote myself a note so I wouldn't forget my thoughts." |
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Apr 4 |
awarded | Necromancer |
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Mar 26 |
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Multiqubit state tomography by performing measurement in the same basis @Piotr Migdal: Using other words I am simply showing that the set of that nonorthogonal measurements is not "informationally complete". |
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Mar 26 |
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Multiqubit state tomography by performing measurement in the same basis Even measurement in single basis produces $2^n-1$ parameters. My preliminary estimation give equation $\sum_k C^n_k C^{k+2}_k$, but seems Chris' curve corresponds a bit different values. |
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Mar 25 |
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Multiqubit state tomography by performing measurement in the same basis Indeed, I see - $\rho_1 = (1 + \sigma_z \otimes \sigma_x)/4$, $\rho_2 = (1 + \sigma_x \otimes \sigma_z)/4$. |
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Mar 25 |
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Multiqubit state tomography by performing measurement in the same basis @Peter Shor: I already wrote, I do not require that - we may distinuish the swap of all components due to assymetry between $\sigma_0 \otimes \sigma_k$ and $\sigma_k \otimes \sigma_0$. |
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Mar 25 |
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Multiqubit state tomography by performing measurement in the same basis @Peter Shor: they are equal only for $k,j \neq 0$ but it is not so for terms with $\sigma_0 =1$ (so my note about "a swap operator" in earlier answer was misleading). |
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Mar 22 |
answered | Multiqubit state tomography by performing measurement in the same basis |
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Mar 9 |
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Analyticity and Causality in Relativity I doubt an answer may be short. From experience of discussion about that problem (also confirmed by answers and comments here) I learn, that even statement of the problem is not very simple. One my colleague even had idea to use it as PhD theme ... |
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Feb 29 |
answered | Quantum memories: What are they? |
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Feb 20 |
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Constructing a Hamiltonian (as a polynomial of $q_i$ and $p_i$) from its spectrum I think, the Newton interpolation formula may be used instead of Gaussian elimination in this case |
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Feb 18 |
answered | Constructing a Hamiltonian (as a polynomial of $q_i$ and $p_i$) from its spectrum |
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Jan 21 |
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Time reversal symmetry and T^2 = -1 I could better understand a question $Pin(3,1)$ vs $Pin(1,3)$. How we could answer what we are using in Euclidean case? Even in Lorentzian case we sometimes have to talk about experimental data (e.g. discovery of antiparticles, search for Majorana neutrino, etc.) to clarify such questions. |
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Dec 5 |
answered | Charged black holes in equilibrium |
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Dec 3 |
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Charged black holes in equilibrium It is quite common to claim that even single black hole does not result a stationary spacetime lightandmatter.com/html_books/genrel/ch07/ch07.html |
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Nov 29 |
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Is this a simple Lie algebra? In such a case OP could write $[i\sigma_a,i\sigma_b]=\cdots$. It is not a convention, it is rather a convenient trick to work with Lie algebra of unitary group, because the algebra is anti-Hermitian matrices. If to use the convention without warning we could not distinguish $sl(2,C)$ and $su(2)$ |
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Nov 24 |
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Hilbert-Schmidt basis for many qubits - reference Maybe the discrete Wigner function is a bit other story, because they need to use trace on $GF(2^n)$ and exchange components in Hilbert-Schmidt scalar product. |