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Apr
20
comment Trying to understand the EPR paradox
Yes it is true that Bell's inequality excludes these more subtle possibilities. But no one believes that those far-fetched possibilites are physically plausible. For the basic behavior of a spinor particle, whose state is defined by the superposition of spin-up and spin-down components, the 100% correlation remains the true paradox and the only paradox.
Apr
16
comment Are eductors working on the Bernoulli principle?
for the outlet, true: but the pressure in the suction chamber can be quite low.
Apr
16
comment Are eductors working on the Bernoulli principle?
And you don't need a supercomputer to figure that out.
Apr
16
comment Are eductors working on the Bernoulli principle?
Yes, you're right about that. I've had lots of discussions about this and I agree with you about the airplane wing. I have only one really good argument for the venturi effect. If you have water in a pipe, and there is a venturi, you agree that the water is flowing faster at the constriction. So it speeds up, and then it slows down. If it slows down, it is decellerating, and there is F=ma to make it slow down. The only force is (pressure)x(area). So the pressure must be higher downstream.
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
@emilio, I am concentrating on your arguments because I think everyone else is an ignoramus who actually believes that the charge density is stationary in the tungsten filament. But a careful reading of everything you have said convinces me that you know I am right, and you have known it from your very first entry when you chose to attack my spelling mistakes instead of my physics; that of course there is a time-varying charge density, but you are using sophistry and mathematics to throw me off.
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
I am not confused.
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
Do you believe that the charge is stationary in a hydrogen atom which is in a superposition of the 1s and 2p states? Or do you agree with me that it is oscillating?
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
I don't care how many PhD's you people have. It is absurd to suggest that in QM, the "average" charge density in a glowing filament is stationary. It's just absurd. I don't know how anyone can believe it.
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
The average charge distribution of EVERYTHING is constant. That is just meaningless. A hydrogen atom in the superposition of 1s and 2p is oscillating rapidly, but the AVERAGE charge distribution is stationary. You don't use the AVERAGE charge to calculate radiation, you use the exact time-varying charge.
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
The notion that a thermal state is constant in time, RIGHT DOWN TO THE MICROSCOPIC CHARGE DISTRIBUTION, is absurd.
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
Because no one else does.
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
well, can we or can't we? Do you agree that there is a time-varying charge distribution?
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
no, it was about whether defining it as a mixed state meant we couldn't talk about the time-varying charge distribution. Did you read the whole question?
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
to be clear: of course there is a time-varying charge distribution. Asyou point out in your answer, the whole universe is in a pure state. That means the charges are distributed somewhere, including the tungsten filament. If you cant FIND the charges by writing down the state function for the isolated tungsten filament...and I don't buy that for one minute...even if you can't, you can still evaluate the wave function of the whole universe. The charges in the tungsten filament are oscillating. It is ridiculous to claim, as Pisanty does, that they are stationary.
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
Pisanty has laid down the claim that because the tungsten filament is in a mixed state, specifically a thermal state, that it we therefore cannot talk about a time-varying charge distribution. In short: the charge is stationary, so classically it cannot radiate. I don't believe this is what Quantum Mechanics tells us, and it's not helpful to try and come up with a better definition of pure vs mixed states. The entanglement with the environment is nothing but a red herring when it comes to the real issue of whether there is a time-varying charge distribution.
Mar
7
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
I think you should let Emilio speak for himself.
Mar
7
comment Quantum entanglement vs classical analogy
Thanks. I'm not used to people agreeing with me.
Mar
7
comment Quantum entanglement vs classical analogy
Because classically, it is perfectly normal for 50% of the light which gets through a vertical polarizer to then also get through a 45 degree offset polarizer. I think Greg is just wrong when he claims a particle that gets through an x polarizer will always be blocked by a y polarizer.
Mar
6
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
So what exactly did you mean last year when you said "black-body radiation can be explained...with discrete energy levels on the emitters rather than the radiation"....what did you mean if not exactly what I am saying?
Mar
6
comment Is a heated tungsten filament in a “pure state” or a “mixed state”?
I'm fine with that.