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Dec
5
comment Testing my understanding of QM - The Double Slit Experiment without the slit
Bingo? I doubt it. Can you use the electrons you've supposedly generated to carry out the OP's experiment? In other words, you create them at will and detect them with certainty in one of two detectors? You method with photons, of course, doesn't work: the detection statistics you get are identical to what you would have for a classical wave whose detection probability is proportional to its intensity. There are no pea-shooters for photons.
Dec
5
comment Decay from excited state to ground state
I'm pretty sure a laser is actually one of the situations where you get exact results if you treat the e-m field classically.
Dec
5
comment Testing my understanding of QM - The Double Slit Experiment without the slit
It's what the OP (David) talked about when he said "we tell the emitter to produce a single electron". We just don't have a way of telling our electron emitters to do that.
Dec
5
answered Testing my understanding of QM - The Double Slit Experiment without the slit
Dec
3
comment Interaction of matter with EM fields
Did you even read my articles?
Dec
2
awarded  Quorum
Dec
2
comment Interaction of matter with EM fields
Of course you know that Lamb never really believed in photons either.
Dec
2
comment Interaction of matter with EM fields
The silver film is the toughest because unlike all your other photon-counting detectors, you don't plug it into the wall. So there's no obvious source for the energy other than the incoming light.
Dec
2
answered Interaction of matter with EM fields
Dec
1
comment Decay from excited state to ground state
I wouldn't object to Ron so much if he called my method "conceptually a bit awkward", although I might disagree with that characterization. I find it tiresome that he calls my reasoning "nonsensical" and "completely wrong".
Dec
1
comment Decay from excited state to ground state
I am not describing BKS theory. BKS predated the Schroeding equation, and my theory depends on the Schroedinger atom. And in my theory there is no need for an atomic transition to be driven completely. Since there are no such things as photons, a passing light wave can partially excite the p state in any number of hydrogen atoms.
Dec
1
answered Decay from excited state to ground state
Nov
30
comment What is the physical sense of the transition dipole moment?
Why must my errors always be gross and my ideas total nonsense? Can I not be capable of subtle errors?
Nov
30
answered Friction between air and a tube
Nov
30
comment What is the physical sense of the transition dipole moment?
Surely you realize I don't understand any of what you're saying.
Nov
30
comment What is the physical sense of the transition dipole moment?
Don't you think it would be more accurate to call me answer "partial nonsense" rather than "total nonsense"?
Nov
29
comment What is the physical sense of the transition dipole moment?
@Vladimir I'm pretty sure that the approximation is virtually exact in the small-dipole case typified by the s-p transition in Hydrogen. And thanks for the props: I'm not used to people agreeing with me.
Nov
29
answered What is the physical sense of the transition dipole moment?
Nov
20
answered What does it take to understand Maxwell's equations?
Nov
20
revised Calculating the gravitational acceleration inside of a planet
elaboration of very sketchy initial answer