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May
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revised Relation between total orbital angular momentum and symmetry of the wavefunction
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comment Relation between total orbital angular momentum and symmetry of the wavefunction
You cannot identify a single microstate with states $|L=2,M_L=1,S=0,M_S=0\rangle$ or $|L=2,M_L=0,S=0,M_S=0\rangle$. For the first one the solution (Clebsch-Gordan coefficients) is: $1/\sqrt{2} (1 \bar{0} ) + 1/\sqrt{2} (0 \bar{1})$ (where $(a b)$ is typically written as a Slater determinant). For the second one, $(L=2 M_L=0) = 1/\sqrt{6} (1 -\bar{1}) + \sqrt{2/3} (0, \bar{0} ) + 1/\sqrt{6} (-1 \bar{1} )$
May
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revised Relation between total orbital angular momentum and symmetry of the wavefunction
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Apr
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answered Relation between total orbital angular momentum and symmetry of the wavefunction
Apr
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answered The approximate uncertainty in $r$
Apr
15
answered Open shells in Quantum mechanics of multielectron atoms
Apr
15
revised How do electron configuration microstates map to term symbols?
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Apr
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revised How do electron configuration microstates map to term symbols?
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Apr
14
answered How do electron configuration microstates map to term symbols?