| bio | website | github.com/Muon |
|---|---|---|
| location | Sydney, Australia | |
| age | 18 | |
| visits | member for | 2 years, 1 month |
| seen | May 5 at 13:21 | |
| stats | profile views | 26 |
Aspiring programmer.
|
Jun 12 |
comment |
How many stars within 5 parsecs? I've updated the script gist. |
|
Jun 12 |
revised |
How many stars within 5 parsecs? Explain what happens if filtering on quality. |
|
Jun 12 |
revised |
How many stars within 5 parsecs? Explain what happens if flagged stars are not counted. |
|
Jun 12 |
comment |
How many stars within 5 parsecs? Also, the Tycho catalog guide, vol. 1 gives the median astrometric precision of all stars as 25 mas or 7 mas for $V_T$ < 9 mag. |
|
Jun 12 |
revised |
How many stars within 5 parsecs? Explain what happens if I discard negative parallaxes. |
|
Jun 12 |
comment |
How many stars within 5 parsecs? That's weird, but OK. So, I should just outright discard negative parallaxes? (I took the absolute value.) What about the "missing" stars in the Hipparcos catalog? |
|
Jun 11 |
comment |
How many stars within 5 parsecs? I don't know, but to double-triple-super-mega-check, I've taken those records apart by hand. Negative parallaxes. |
|
Jun 11 |
comment |
How many stars within 5 parsecs? See cdsarc.u-strasbg.fr/viz-bin/Cat?I/239#sRM2.13 And why couldn't those be parallax values? Also, I initially did use the delimited field approach, but I got the same results. I switched to fixed offsets because it ran faster. |
|
Jun 11 |
revised |
How many stars within 5 parsecs? Fixed typos. |
|
Jun 11 |
comment |
How many stars within 5 parsecs? This is the script I used: gist.github.com/2912916 |
|
Jun 11 |
asked | How many stars within 5 parsecs? |
|
Mar 30 |
awarded | Scholar |
|
Mar 30 |
awarded | Supporter |
|
Mar 30 |
awarded | Student |
|
Mar 30 |
accepted | Amplitude at distance from source |
|
Mar 30 |
awarded | Editor |
|
Mar 30 |
revised |
Amplitude at distance from source replaced \thicksim with \sim |
|
Mar 30 |
comment |
Amplitude at distance from source So, er, $A^2 \sim \frac{1}{x^2}$ and therefore $A \sim \frac{1}{x}$? |
|
Mar 30 |
asked | Amplitude at distance from source |
|
Mar 30 |
awarded | Autobiographer |