# José Figueroa-O'Farrill

less info
reputation
617
bio website maths.ed.ac.uk/~jmf location Edinburgh, Scotland age 50 member for 2 years, 11 months seen yesterday profile views 193

I am a mathematical physicist at the Maxwell Institute for Mathematical Sciences and the School of Mathematics of The University of Edinburgh, in sunny Scotland. I am a founding member of the Edinburgh Mathematical Physics Group and regular contributor to its blog.

# 86 Actions

 1d awarded Supporter Jan10 comment How can I show non-Abelian CS term is a total derivative? @FedericoCarta If you expand the RHS, itâ€™s not obviously a total derivative. It requires use of Leibniz and then showing that what remains outside of the derivative is zero. If you expand the RHS and use Bianchi you get pretty much the LHS on the nose. Jan9 comment How can I show non-Abelian CS term is a total derivative? Just expand the RHS! (And you'll have to use the Bianchi identity.) Mar27 awarded Yearling Mar14 awarded Enlightened Mar14 awarded Nice Answer Jan12 awarded Nice Answer Sep19 awarded Nice Answer May5 awarded Nice Answer May4 awarded Enlightened May4 awarded Enlightened May4 awarded Nice Answer May4 awarded Yearling May4 awarded Nice Answer May4 awarded Teacher May4 awarded Student May4 awarded Commentator May4 awarded Nice Question May4 awarded Nice Answer Jan1 comment Some questions on a version of the O'Raifeartaigh model A brief comment on your first question: the superpotential is a holomorphic function, hence complex unless (locally) constant. It appears in the lagrangian density as the real part of its integral over "half the superspace". Chiral superfields are therefore complex: indeed they define holomorphic coordinates on a Kähler manifold.