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like to play badminton


Apr
26
awarded  Autobiographer
Mar
8
comment Equivalence classes of mappings from $T^{2}$ to an arbitrary space $X$
$\pi_2(T^2)=0$ is not?
Feb
18
awarded  Supporter
Feb
2
comment Why does non-commutativity in quantum mechanics require us to use Hilbert spaces?
KCd - it should be a vector space (to have linearity) with Fourier transform defined, i.e., with scalar product. Does it mean - Hilbert space, right?
Feb
1
answered Why does non-commutativity in quantum mechanics require us to use Hilbert spaces?
Jan
16
comment Controlled-measurement of a quantum register
hope, you may find the answer in: physics.stackexchange.com/questions/26869/…