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Aug
17
awarded  Custodian
Aug
17
reviewed Approve Generalization of De Rham cohomology for spinor fields
Aug
11
revised Instantons in Witten's supersymmetry and Morse theory
added 7 characters in body
Aug
9
comment How to include Berry connection in Hamiltonian?
@Chinmayee The answer of your first question is positive $\mathcal{H}(R) = E(R)$, which is the Hamiltonian function on the parameter space. For your second question I added an update to the answer.
Aug
9
revised How to include Berry connection in Hamiltonian?
added 877 characters in body
Aug
5
answered How to include Berry connection in Hamiltonian?
Jul
29
revised Diagonal part of the configuration space of two indistinguishable quantum particles
edited body
Jul
29
answered Diagonal part of the configuration space of two indistinguishable quantum particles
Jul
7
answered Can the Berry Connection be derived from a metric?
Jul
3
awarded  Good Answer
Jun
27
revised Generalization of De Rham cohomology for spinor fields
added 6 characters in body
Jun
27
answered Generalization of De Rham cohomology for spinor fields
Jun
3
answered Geometric measure of entanglement in example with GHZ state
May
21
comment If a symmetry operator S in a QFT annihilates the vacuum, why does S preserve the space of 1-particle states?
@Void 2) Assuming Lorentz symmetry, the renormalization factors Z in ψ R =Z(ψ)ψ are Lorentz scalars, thus nothing essential changes in the analysis when the true renormalized field is used: Its transformation properties remain the same.
May
21
comment If a symmetry operator S in a QFT annihilates the vacuum, why does S preserve the space of 1-particle states?
@Void 1) Please think for a moment of $Q$ as the electric charge operator, you can write it uzing the Gauss' law as a surface integral of the electric field over a very large sphere at infinity. Due to the large distance these fields do not produce singularities when multiplied by other fields, thus the only singualrities coming from the commutator are those due to the local field $\psi$, thus the commutator itself is also a local field at $x$.
May
14
revised If a symmetry operator S in a QFT annihilates the vacuum, why does S preserve the space of 1-particle states?
added 12 characters in body
May
14
answered If a symmetry operator S in a QFT annihilates the vacuum, why does S preserve the space of 1-particle states?
May
5
comment The $U(1)$ charge of a representation
@JakobH The generator of the U(1) charge $Y_{\gamma}$ needs by definition to commute with all root generators $E_{\gamma}$ of the unremoved nodes. The Cartan-Weyl generator $H_i$ corresponding to the removed node does not possess this property, but its dual (called a coweight) does. The duality transformation can be accomplished on weight space by means of the metric tensor.
May
5
awarded  Nice Answer
Mar
11
awarded  Revival