network profile
| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 3 months |
| seen | May 4 at 12:33 | |
| stats | profile views | 3 |
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Feb 20 |
asked | Beta decay for Ar-38, K-38, Cl-38 |
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Feb 20 |
awarded | Scholar |
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Feb 20 |
accepted | $\alpha$ decay to more than one nuclear state |
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Feb 20 |
awarded | Editor |
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Feb 20 |
comment |
$\alpha$ decay to more than one nuclear state Ok I think I understand, all that I'm unsure of now is for the example decay, (which is only from class notes, but I will assume to be true) why the ground state cannot be reached by the decay. When you grab two protons and neutrons, why can you not take the highest energy ones and thus be in the $^{237}Pm$ ground state |
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Feb 20 |
revised |
$\alpha$ decay to more than one nuclear state added 56 characters in body |
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Feb 20 |
awarded | Supporter |
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Feb 20 |
awarded | Student |
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Feb 20 |
asked | $\alpha$ decay to more than one nuclear state |
