# user21119

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# 71 Actions

 May22 revised Path Integrals Page Peskindeleted 30 characters in body; edited title May9 comment Contracting the Riemann tensor issues, p540 hobsonit is not but i have done it now anyway May2 comment Singularities in Schwarzchild space-timeyeah thx, so would it be r=0 geometric and then r=2GM co-oridante May1 comment Singularities in Schwarzchild space-timeIs the singulatiry when the coeficient goes to $\infty$ so at r=0 and at infinity? May1 asked Singularities in Schwarzchild space-time Apr28 revised Discretization of action in path integraladded 2 characters in body Apr28 comment Discretization of action in path integralI thinks so, does this mean that $k\Delta t=t$?, Sorry i didnt put this in but it is actually $S=T-V dt$ not $dx$ Apr28 comment Discretization of action in path integralIm sorry I don't follow from maths line 2 to 3 why has the denominator disappeared? Apr27 asked Discretization of action in path integral Apr19 revised Poles bit in a propagatordeleted 478 characters in body Apr19 revised Path Integrals Page Peskindeleted 610 characters in body Apr19 accepted Poles bit in a propagator Apr19 comment Poles bit in a propagatorThanks I get it now Apr19 comment Poles bit in a propagatorSorry I am getting muddled with conventions firstly is $E_{p}^{2}=m^{2}+p^{2}_{i}$, also shouldn't the exponentials have a $p$ not an $E_{p}$, I don't really see why there is a $p^{2}-m^{2}$, sorry for being awkwrd Apr19 comment Poles bit in a propagatorsorry I am still a bit confused, I dont see how you did the last integral. I realise that p can be split into $p^{0}$ and its spatial terms but i stil cant see how to do the last integral Apr19 asked Poles bit in a propagator Apr18 asked Path Integrals Page Peskin Apr11 asked What does Planck/WMAP/COBE actually measure when studying the CMB? Apr8 awarded Disciplined Apr8 comment Contracting the Riemann tensor issues, p540 hobsonsurely though the $g^{\alpha \rho}$ takes away this index? If not thewn is $g_{\sigma\alpha}g^{\alpha rho} \Gamma^{\sigma}_{\mbox{ }\mu \rho}=\Gamma^{\rho}_{\mbox{ }\mu \rho}$