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Feb
21
comment Covariant derivative
In GR the connection is assumed to be torsion-free, so the Levi-Civita connection is all that is discussed in most introductory texbooks. Other connections are possible though, and the covariant derivative depends on the type of connection. If you're just learning GR then you don't really need to worry about any of that though.
Feb
21
answered Covariant derivative
Feb
21
answered Null geodesic given metric
Feb
21
answered Lagrange-Euler equations for a bead moving on a ring
Feb
21
awarded  Commentator
Feb
21
comment Electric field caused by magnetic field
The way E fields are generated is given to us by Maxwell's equations, and the equation for finding the E field produced by a charge and the equation for finding the E field produced by a changing B field are different.
Feb
21
answered Conservative Force and $1/r^2$
Feb
21
comment Electric field caused by magnetic field
No. The electric field around the solenoid looks similar to the magnetic field around straight current. I.e. it looks similar to the field in: school-for-champions.com/science/images/… .
Feb
21
answered Electric field caused by magnetic field
Feb
19
comment What are the biggest unanswered questions in physics today?
@hkBattousai I didn't know medical doctors used quantum mechanics :P.
Feb
17
comment Why is $\langle \partial_{\mu} f(x) \rangle=0$?
I don't own the books so I can't really determine the context. Could it have to do with the fact that the average amplitude of a sinusoidal wave is zero?
Feb
17
awarded  Informed
Feb
17
accepted Does Kaluza-Klein Theory Require an Additional Scalar Field?
Feb
17
comment Does Kaluza-Klein Theory Require an Additional Scalar Field?
Why is $g_{55}$ necessarily a scalar field? What's the motivation to promote it from being a constant to a field? Is it just because a 5th dimension with variable size is more general?
Feb
17
comment Does Kaluza-Klein Theory Require an Additional Scalar Field?
My sources are: weylmann.com/kaluza.pdf math.arizona.edu/~vpiercey/KaluzaKlein.pdf I'm not sure why you say applying the the action principle on the 5D Ricci scalar naturally implies an additional field. When considering the second form of the metric in my OP, isn't the Ricci scalar just: $\tilde{R}=R+\frac{k}{4}F^{\mu \nu}F_{\mu \nu }$ If $k$ is a constant I don't see how that implies a scalar field.
Feb
17
answered How do you calculate angle of projection?
Feb
17
asked Does Kaluza-Klein Theory Require an Additional Scalar Field?
Feb
17
revised Faraday's Law and Galilean Invariance
added 102 characters in body
Feb
17
answered Faraday's Law and Galilean Invariance
Feb
15
answered Plotting the maxwell-Boltzmann velocity distribution in matlab