| bio | website | |
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| visits | member for | 4 months |
| seen | May 16 at 9:36 | |
| stats | profile views | 31 |
work at Licensario.
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Apr 19 |
comment |
Explanation for the next steps of chaplygin dipole Thank you very much for your explanation!! I believed I will understand it if someone would explain me in other words, but I didn't believe how much I would understand! thank you!! |
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Apr 19 |
accepted | Explanation for the next steps of chaplygin dipole |
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Apr 18 |
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Explanation for the next steps of chaplygin dipole @ChristophB. I can understand the steps if the explanation will be more clear.. can you tell me please what is the passing from (2.5) to (2.6) and from (2.6) to (2.7)? which actions of algebra did he use to reach the solution? (I guess that so he got b=3.8317). thank you a lot! if you want, you can write me the answer in "answer the question" and I will accept it. anyway, you can to the same thing in my other question: physics.stackexchange.com/questions/61460/… thank you!! |
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Apr 18 |
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coordinate change differential equation polar @ChristophB. thank you Christoph! it helped me! |
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Apr 17 |
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coordinate change differential equation polar I know but here I'm just asking for the step (2.5). |
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Apr 17 |
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Explanation for the next steps of chaplygin dipole @ChristophB. I understood till (2.4) included. what's about the next steps please? thank you very much! :] |
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Apr 17 |
asked | coordinate change differential equation polar |
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Apr 17 |
revised |
Explanation for the next steps of chaplygin dipole added 148 characters in body |
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Apr 17 |
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Explanation for the next steps of chaplygin dipole @Bernhard, can you explain me please? thank you very much!! |
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Apr 16 |
asked | Explanation for the next steps of chaplygin dipole |
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Mar 19 |
awarded | Editor |
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Mar 9 |
awarded | Supporter |
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Mar 9 |
accepted | $\nabla({\bf u}^2)=2({\bf u}\cdot \nabla){\bf u} - 2(\nabla \times {\bf u}) \times {\bf u}$ |
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Mar 9 |
asked | $\nabla({\bf u}^2)=2({\bf u}\cdot \nabla){\bf u} - 2(\nabla \times {\bf u}) \times {\bf u}$ |
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Mar 9 |
accepted | Bernoulli's theorem: $\frac{p}{\rho}+\frac{1}{2}u^2+\phi$ is constant along a streamline |
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Mar 8 |
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Bernoulli's theorem: $\frac{p}{\rho}+\frac{1}{2}u^2+\phi$ is constant along a streamline sorry, I forgot to paste the link: www3.kis.uni-freiburg.de/~peter/teach/hydro/hydro02.pdf |
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Mar 8 |
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Bernoulli's theorem: $\frac{p}{\rho}+\frac{1}{2}u^2+\phi$ is constant along a streamline @dmckee, in (2.13) you can find the definitions. thank you! |
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Mar 8 |
awarded | Student |
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Mar 8 |
asked | Bernoulli's theorem: $\frac{p}{\rho}+\frac{1}{2}u^2+\phi$ is constant along a streamline |
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Mar 6 |
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What does Euler equation mean? thank you both.. sorry for my english.. I give an example: Pythagorean theorem (a^2+b^2=c^2) means that in a right triangle, a^2+b^2=c^2 where: c represents the length of the hypotenuse, and a and b represent the lengths of the other two sides. thank you both! |