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 Jan 8 awarded Yearling Dec 15 awarded Notable Question Dec 3 awarded Popular Question Nov 12 awarded Notable Question Aug 23 awarded Popular Question Jun 20 comment Human max speed in open space @Rodolphe What then? I thought we were talking Newtonian. But if you see curved spacetime, then it's because there's an interaction with something producing that curvature. Jun 20 answered Human max speed in open space Jun 16 comment Why is the Baryon Acoustic Oscillations (BAO) calculated like this? @ChrisWhite I know, I was really surprised. I rephrased the question to make it independent of that wikipedia page. Jun 16 revised Why is the Baryon Acoustic Oscillations (BAO) calculated like this? added 811 characters in body Jun 15 asked Why is the Baryon Acoustic Oscillations (BAO) calculated like this? Jun 4 revised Can we assume black hole is just two big stars revolving around each other? added 2 characters in body Jun 4 revised Can we assume black hole is just two big stars revolving around each other? added 8 characters in body Jun 4 revised Can we assume black hole is just two big stars revolving around each other? deleted 5 characters in body Jun 4 comment Can we assume black hole is just two big stars revolving around each other? Downvote why? Nothing I said was wrong, it was a completion to the answers. Jun 4 comment Turning points of particle @RafaFafa You're welcome! Jun 4 answered Turning points of particle Jun 4 answered Can we assume black hole is just two big stars revolving around each other? May 15 comment What is the length dimension in critical phenomena? Hm, I had $\xi$ defined as $$\xi^2=\frac{\int_0^\infty r^2G(r)}{\int_0^\infty G(r)}$$ But anyway, I know the expression of the correlation function in the three regimes, I just fail to see why I should expect values that don't depend on the size of the system for dimensionless variables. Thank you for answering May 15 comment What is the length dimension in critical phenomena? @MengCheng I think it's the word length that confused me, sorry. For example the Binder cumulant as defined in the previous question ($\langle m^4\rangle/\langle m^2\rangle^2$) is dimensionless, why should it be better that $\xi/L$ to find the critical point? May 15 comment What is the length dimension in critical phenomena? @Danu Well, I know what a dimesionless variable is. I just don't know how that applies. If a quantity is dimensionless, then in a scale invariant system, it should not depend on size. Is that it? Why? And if so, should any dimensionless quantity I could build behave that way? For example, if the susceptibility goes like $\chi\sim L^{\gamma/\nu}$, then $\chi/L^{\gamma/\nu}$ behaves that way although it has dimensions.