user50229

178 reputation

	178 reputation	bio	website		visits	member for	4 months
6 badges		location			seen	May 15 at 14:42

11 Actions

Jan 3	comment	Books that every physicist should read @AdamRedwine Books do not win Nobel Prizes, people do
Jan 2	comment	Why are expressions such as $\operatorname{ln}T$ used in thermodynamics where $T$ is not dimensionless? But mathematically I think you cannot even perform this separation as $\operatorname{ln}(T K)$ does not exist in the first place. I am more inclined to agree with the previous answer - I think this is a sloppy shortcut which isn't truly valid.
Jan 1	awarded	Scholar
Jan 1	accepted	Why are expressions such as $\operatorname{ln}T$ used in thermodynamics where $T$ is not dimensionless?
Jan 1	awarded	Nice Question
Dec 31	awarded	Supporter
Dec 31	awarded	Editor
Dec 31	revised	Why are expressions such as $\operatorname{ln}T$ used in thermodynamics where $T$ is not dimensionless? spelling correction
Dec 31	awarded	Student
Dec 31	asked	Why are expressions such as $\operatorname{ln}T$ used in thermodynamics where $T$ is not dimensionless?
Dec 31	awarded	Autobiographer