|visits||member for||1 year, 10 months|
|seen||Jan 8 '13 at 20:09|
Rolling (without slipping) ball on a moving surface
Thanks very much @Raindrop. Can you explain what the "normal force" I am missing entail? I thought the normal force is what the surface exerts on the ball to counter the normal component of the gravitational force the ball is exerting on the surface. I thought that this component would be cancelled, leaving the mgsinθ component only. Could you explain more of how that works? Is it because the arc swinging up would give it an additional 'lift'? Thanks for your help!