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| visits | member for | 2 years, 3 months |
| seen | Mar 24 at 4:55 | |
| stats | profile views | 56 |
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Jan 18 |
comment |
What's the role of classically forbidden paths in path integral? It doesn't have to be the "smallest value of S", classical paths must only be extrema of the action functional |
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Jun 11 |
accepted | Connection between Poisson Brackets and Symplectic Form |
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Jun 11 |
comment |
Connection between Poisson Brackets and Symplectic Form Thanks for the clarification. It still doesn't make any sense to me why they chose such confusing way to present this, but at least I understand what happened now. I do have to say though that in my version of the book (also from 1998) the matrix you have in eq. 5.43 is for $ \Omega ^{-1}$ not $\Omega$, and as a result your matrix after "we conclude..." should be $ \Omega $. It doesn't change anything else you pointed out, but could create confusion for someone else. |
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Jun 11 |
awarded | Yearling |
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Jun 8 |
awarded | Constituent |
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Jun 8 |
awarded | Caucus |
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Apr 5 |
awarded | Critic |
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Mar 10 |
awarded | Quorum |
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Mar 10 |
awarded | Commentator |
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Mar 10 |
comment |
Connection between Poisson Brackets and Symplectic Form I do not see how you answered the confusion exposed on my post. I know the matrices representing the PB and the symplectic form are inverse to one another, the problem lies on their representation, i.e., in the (q,p) representation w^{ij} have to be the matrix elements of the symplectic matrix so we get the right expression for the PB (if the order of the \xi are q1,q2,p1,p2, for example). Whereas, if I use w_(ij) as the matrix elements of the inverse of omega to obtain the symplectic form I get (again in the q,p rep), w = - dq ^ dp instead of w = dq ^ dp. |
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Mar 10 |
revised |
Connection between Poisson Brackets and Symplectic Form added 2 characters in body |
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Mar 9 |
asked | Connection between Poisson Brackets and Symplectic Form |
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Nov 26 |
accepted | Number of conditions for a two-particle state to be decomposable |
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Nov 26 |
comment |
Number of conditions for a two-particle state to be decomposable $x$ is supposed to represent a three dimensional vector. Sorry if that was unclear, maybe I should have written it in bold. |
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Nov 26 |
asked | Number of conditions for a two-particle state to be decomposable |
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Apr 13 |
comment |
Phase shifts in scattering theory "For a typical potential" is a very vague statement. It would be better perhaps to say "in the limit of low energy scattering". |
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Mar 4 |
awarded | Scholar |
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Mar 4 |
accepted | What is the mechanism of dielectric saturation? |
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Mar 4 |
revised |
What is the angular momentum spectrum of an sp${}^3$ electron? Reply to comment by Ted Bunn (too long for the comments section) |
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Mar 3 |
answered | What is the angular momentum spectrum of an sp${}^3$ electron? |