network profile
| bio | website | |
|---|---|---|
| location | ||
| age | ||
| visits | member for | 5 months |
| seen | Mar 27 at 10:38 | |
| stats | profile views | 13 |
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Jan 12 |
answered | Estimating atmospheric friction by measuring the change in velocity of a ball thrown straight upwards |
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Jan 11 |
comment |
equivalence of wave equations yes, my argument is only applicable to functions. Nevertheless what sort of behaviour is to expect around $t=0$? I think that this is just a "step" of height $s(\vec r)$, then $t$-derivative gives $\delta(t) s(r)$, second derivative gives $\delta'(t)s(r)$. The second equation would give the same if we assumed additionally that $\psi(t<0,\vec r)=0$. I guess then the solution may in fact be just a discontinous function around $t=0$ (and of course a distribution by local integrability). The problem is the second equation does not gieanything special about $t<0$ |
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Jan 9 |
comment |
equivalence of wave equations how is it possible that $\psi(vec r, t)$ can be both equal to $s(\vec r)$ and on the other hand to zero? Except for $s=0$ that is... |
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Jan 9 |
comment |
equivalence of wave equations what do you mean by equivalent? The initial conditions for $\psi(\vec r,0)$ are different provided $s\not \equiv 0,$ so there exists no function that solves both of them |
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Dec 30 |
comment |
What entities in Quantum Mechanics are known to be “not quantized”? by "closed" you actually mean "compact" ? |
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Dec 27 |
awarded | Editor |
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Dec 27 |
revised |
Level of calculus required for physics added 1 characters in body |
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Dec 27 |
comment |
Level of calculus required for physics Quantum mechanics requires understanding of linear algebra, then analysis on Hibert spaces. Calculus is useful as well but mainly to solve problems during classes. The only really badly needed thing from calculus is "series method" and solving linear ODE of second order under different boundary conditions. |
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Dec 27 |
comment |
Level of calculus required for physics "Methods of Modern Mathematical Physics" - this i s a series of 4 books. |
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Dec 26 |
answered | Level of calculus required for physics |
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Dec 21 |
answered | Intuition behind Fourier transformed spaces |
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Dec 20 |
awarded | Supporter |
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Dec 20 |
answered | Why don't I feel pressure on my body when swimming under water? |
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Dec 19 |
comment |
Can you tell if a particle is in superposition? So it means that you do not need a state after measurement any more... nevertheless 0 for "eigenstate" and 1 for "superposition" is very inefficient, as you map virtually whole Hilbert space to 1, and measure 0 set to bit 0. Moreover I think this is also very impractical in general. |
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Dec 19 |
answered | Can you tell if a particle is in superposition? |
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Dec 19 |
awarded | Teacher |
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Dec 19 |
answered | Intuitive explanation of the inverse square power $\frac{1}{r^2}$ in Newton's law of gravity |
