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| bio | website | agooddayinabadtown.com |
|---|---|---|
| location | Boulder, Colorado, USA | |
| age | 20 | |
| visits | member for | 5 months |
| seen | Apr 5 at 19:48 | |
| stats | profile views | 27 |
I currently work as a database administrator for CU Boulder's Laboratory for Atmospheric and Space Physics.
I am also working on my BS in Engineering Physics with a minor in Computer Science at CU Boulder... because I didn't want weekends anyways. ;)
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Jan 23 |
answered | Why can we say there is no tangential acceleration in this specific problem? |
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Jan 23 |
comment |
Why can we say there is no tangential acceleration in this specific problem? Precisely. I will write this up as an answer and you can close this out... glad I could help! |
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Jan 23 |
comment |
Why can we say there is no tangential acceleration in this specific problem? To clarify, if you are interested in only the exact instant shown above, then indeed each cart's tangential acceleration is the same (and is 0). This is because the tangential component of the acceleration due to gravity on cart 3 is in the opposite direction (tangentially) as cart 1 at this instant, and thus the net tangential acceleration due to gravity on the train at this instant is zero (therefore tangential acceleration on each cart is also zero since they are connected). At this instant, thus, the only acceleration is normal and equals v^2/r for each cart, as suggested. |
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Jan 23 |
comment |
Why can we say there is no tangential acceleration in this specific problem? Are we to also assume that there is no gravity in this situation? If gravity is taken into effect, then the only point at which there actually isn't a tangential component of acceleration is at the very top of the loop. |
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Dec 21 |
answered | Angular momentum power plant on Earth |
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Dec 20 |
reviewed | Reviewed Rolling (without slipping) ball on a moving surface |
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Dec 20 |
suggested | suggested edit on Rolling (without slipping) ball on a moving surface |
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Dec 20 |
awarded | Custodian |
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Dec 20 |
reviewed | Reviewed First class and second class constraints |
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Dec 13 |
answered | How to relate speed of sound with relative humidity? |
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Dec 11 |
answered | Classical mechanics and the speed of a train-mosquito collision, when perfectly rigid bodies |
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Dec 6 |
awarded | Organizer |
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Dec 6 |
revised |
Temporal part of Quantum Wavefunction improved formatting |
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Dec 6 |
suggested | suggested edit on Temporal part of Quantum Wavefunction |
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Dec 5 |
awarded | Critic |
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Dec 5 |
awarded | Citizen Patrol |
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Dec 5 |
comment |
Projectile Motion with Air Resistance and Wind Consider the system in the exact same manner as you would without wind resistance, and then draw a free body diagram and look at acceleration and forces on the projectile. The only thing that air adds to the scenario is the frictional force, always in a direction opposite the projectile's movement. Thus, you should simply change the free body diagram to include this force and re-calculate the horizontal and vertical components of acceleration. As to your confusion about v*vx, v is the magnitude of the projectile's velocity relative to the air, vx is the x component of this velocity vector. |
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Dec 5 |
answered | Projectile Motion with Air Resistance and Wind |
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Dec 5 |
comment |
Projectile Motion with Air Resistance and Wind If you are seeking an answer with a high degree of accuracy, this becomes a HUGELY complex problem dependent on multiple variables including shape of the projectile, pressure/temperature of the air, and a number of other factors. How precise an answer do you need? |
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Dec 4 |
comment |
Confused on how to properly use right hand rule Sure thing. Glad you figured it out! |
