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I once got busy in a Burger King bathroom.


Jun
11
comment How to construct an isomorphism between the Complexified Special Linear Lie Group and the Special Unitary Group?
See physics.stackexchange.com/questions/47339/… for some explanation of how these groups and algebras fit together.
Apr
2
comment Cluster decomposition in string theory
How do you want to formulate the cluster decomposition principle? The version discussed on wikipedia doesn't work well for string theory, which lacks gauge invariant local operators.
Mar
25
answered Looking for intro to Conformal Bootstrap
Feb
24
comment Are electron fields and photon fields part of the same field in QED?
@StanShunpike: Zee does in fact discuss Yang-Mills theory. First in the subsection labelled non-abelian gauge theory and then in more detail in the chapter on GUTs.
Feb
19
answered Is a constant transformation still considered a gauge transformation?
Jan
21
awarded  Yearling
Dec
4
comment The index of a Dirac operator and its physical meaning
"Witten's paper from the 1980s"... Witten must have written 100 papers in the 1980s. Which one are you reading?
Nov
4
comment Are there QFTs in which a field cannot produce a real particle?
Also, conformal field theories don't have particle excitations.
Nov
1
comment What is the meaning of a state in QFT?
You can't in general identify states with fields. Any operator -- including a field operator -- creates a state. But it's not the case that two different operators must create different states.
Nov
1
comment What is the meaning of a state in QFT?
Sure, but those VEVs are amplitudes between certain states. It's really not any different from QM.
Nov
1
comment What is the meaning of a state in QFT?
QFT is a quantum theory. It has states just as any quantum theory has states. Why do you say that states don't make sense in QFT?
Oct
15
accepted Classic Literature in Quantum Gravity?
Sep
30
awarded  Explainer
Sep
24
awarded  Autobiographer
Sep
9
answered Moduli spaces in string theory vs. soliton theory
Jul
27
awarded  Pundit
Jul
10
comment A rigorous treatment of distributions in quantum mechanics
See also: physics.stackexchange.com/q/43515
Jul
4
awarded  Nice Answer
Jun
29
comment QFT's that have no action
Probably easier to get the definition right just by saying how the field transforms under special conformal transformations.
Jun
29
comment QFT's that have no action
The nontrivial half of the state-operator correspondence is gotten by shrinking a sphere down to a point where the operator is defined. Apply state-operator correspondence to eigenvector and you get a field.