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I once got busy in a Burger King bathroom.


Jul
27
awarded  Pundit
Jul
10
comment A rigorous treatment of distributions in quantum mechanics
See also: physics.stackexchange.com/q/43515
Jul
4
awarded  Nice Answer
Jun
29
comment QFT's that have no action
Probably easier to get the definition right just by saying how the field transforms under special conformal transformations.
Jun
29
comment QFT's that have no action
The nontrivial half of the state-operator correspondence is gotten by shrinking a sphere down to a point where the operator is defined. Apply state-operator correspondence to eigenvector and you get a field.
Jun
29
comment QFT's that have no action
I'm afraid your edits have made your answer slightly confusing. The Virasaro algebra, on the other hand, is peculiar to 2-dimensional CFT. In general CFTs, one defines primary fields by looking for eigenvectors of the dilation operator.
Jun
28
comment QFT's that have no action
The state-operator correspondence is a feature of CFT in general, not just two-dimensional CFT. Likewise, the use of primary fields to generate the algebra of observables via OPE works in any d-dimensional CFT.
Jun
28
comment Perturbative vs. non-perturbative approaches to a well-defined Yang-Mills theory in 4 dimensions
Yes, of course @TobiasDiez meant $e^{-1/g^2}$.
Jun
25
comment Rigorous QFT on a Torus
You can't avoid dealing with color confinement once the spacetime volume is large enough. This is the big obstacle, the one the Clay prize is aimed at.
Jun
25
comment Rigorous QFT on a Torus
Yes. The problem is that the infinite volume limit leads to divergences not present in finite volume. These divergences reflect real physics; they tell you that the gluons are confined on long distance scales.
Jun
25
comment Rigorous QFT on a Torus
I'm sorry: Are you asking if its harder to construct YM on a torus than on $\mathbb{R}^4$?
Jun
25
answered Rigorous QFT on a Torus
Jun
25
awarded  mathematical-physics
Jun
24
comment Rigorous QFT on a Torus
Did you look in the references of the paper you're quoting?
Jun
24
revised Why isn't Quantum Yang-Mills Rigorous?
added 4 characters in body
Jun
24
answered Why isn't Quantum Yang-Mills Rigorous?
Jun
16
comment Why gauge $SU(N)$ and not $SO(N)$?
I don't think you get any substantially new phenomena by choosing an SO(N) gauge group. The different representations mean we get different charges for the fermions, but the basic physics of Yang-Mills theory works the same way for any compact gauge group.
Jun
16
revised Is the graviton hypothetical?
added 20 characters in body
Jun
16
comment Is the graviton hypothetical?
@Anixx: Why don't you ask that question in a separate post? This isn't really a good place to discuss it.
Jun
16
answered Is the graviton hypothetical?