B. Elliott
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 Jan 19 awarded Notable Question Nov 12 awarded Popular Question Jul 6 comment What exactly are we doing when we set $c=1$? Observed velocity of a light beam is always c, no matter the reference frame you're in. However, observed velocity of one's own reference frame is always 0 for an observer in that frame. An observer could choose a reference frame that's moving with respect to themselves, but it's usually easier (for the math) to consider the origin of the observer's reference frame fixed on the observer. Good instincts keeping an eye out, but internal reference frame velocity is typically zero. Semantics, heh. May 14 comment Would this be a metric? Good answer. Generally, a metric has to be nondegenerate (as Ben notes), symmetric (that is, switching rows to columns and vice-versa for the matrix representation gives you the same metric), and bilinear (vector arguments passed to the metric can be subdivided linearly). Anything else following tensor rules is allowed. May 11 awarded Critic Feb 26 accepted Relationship between a formal vector derivative and time evolution of an operator Feb 26 comment Relationship between a formal vector derivative and time evolution of an operator Yes on the term rather than component- inaccurate wording there, sorry. Also good clarification on the connection to classical mechanics. Won't edit them, so that other people with similar misconceptions can correct them. Feb 26 asked Relationship between a formal vector derivative and time evolution of an operator Jan 27 awarded Informed Jan 27 awarded Analytical Jan 26 comment Quantum Computing Power Advantages A nicely succinct answer; I still have to go with the other one thanks to the rousing entropy discussion. Cheers! Jan 26 accepted Quantum Computing Power Advantages Jan 25 awarded Student Jan 25 awarded Supporter Jan 25 asked Quantum Computing Power Advantages Jan 24 awarded Scholar Jan 24 accepted Dense Spherical Black Hole Shell with a Region Inside Jan 24 asked Dense Spherical Black Hole Shell with a Region Inside Jan 21 comment What exactly are we doing when we set $c=1$? By setting $c=1$, we still have a scale- it is simply in units of $c$. That is, I could say my velocity is 0.1 speeds of light. Jan 21 awarded Teacher