190 reputation
9
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location Pasadena, CA
age 22
visits member for 2 years, 5 months
seen Feb 9 at 0:06

Feb
5
accepted Multivariable functions of Grassmann numbers
Feb
5
asked Multivariable functions of Grassmann numbers
Jan
4
awarded  Popular Question
Jul
22
revised Is topology of universe observable?
Removed unnecessary statement of opinion.
Jul
22
suggested approved edit on Is topology of universe observable?
Jul
8
answered Sold-State Band Structure - connection between Fermi Energy, Fermi Level and Work Fuction
Jul
4
comment Kinetic energy in Lagrangian formalism
But that is not one of the assumptions.... if we assumed that $\frac{\partial r}{\partial t} = 0$ then the system would be stationary? Instead we assume that the $q_i$ (as functions of $r_i$) do not depend on time explicitly.
Jul
4
asked Partial derivatives in Lagrangian formalism
Jul
4
asked Kinetic energy in Lagrangian formalism
Jul
2
awarded  Curious
May
31
revised Electric field of a dipole
corrected for a factor of r
May
31
comment Electric field of a dipole
Thank you for a very complete and intuitive answer. One question, though: why is $\hat{\theta} \sim \hat{r}\times(\hat{r}\times\mathbf{d})$?
May
31
accepted Electric field of a dipole
May
30
comment Electric field of a dipole
@Tobias Right, I know that those are /supposed/ to be equal, but I'm trying to figure out how to show that they are.
May
29
asked Electric field of a dipole
Apr
23
comment Why do we need non-trivial fibrations?
^That would be much appreciated. The math S.E. answer seems a little hard to parse. Here is another very related question: two-qubit systems are often represented as the Hopf fibration $S^3\hookrightarrow S^7\rightarrow S^4$ (and analogously for three qubits) - are these representations unique? Reasoning as in my PS above I see that we need a base of $S^4$, that our full space is $S^7$, and that a trivial tensor product won't do - is the Hopf fibration a unique nontrivial fibration of $S^7$ with base $S^3$?
Apr
22
accepted Intuition behind Fourier transformed spaces
Apr
22
awarded  Commentator
Apr
22
comment Why do we need non-trivial fibrations?
You seem to assume that we want our space to locally look like $S^2\times S^1$ - why? Perhaps there is another way to 'twist and glue the spaces' to get $S^3$ from $S^2$? I agree that the fibration cannot be globally a trivial product, but why do we limit ourselves to Hopf?
Apr
22
asked Why do we need non-trivial fibrations?