137 reputation
26
bio website
location
age
visits member for 1 year, 9 months
seen Apr 22 '13 at 18:57

May
23
awarded  Notable Question
Apr
18
awarded  Notable Question
Oct
3
awarded  Popular Question
May
16
awarded  Popular Question
Apr
22
awarded  Supporter
Apr
22
comment Three polarizers, 45° apart
Exactly what I was looking for. Thank you!
Apr
22
accepted Three polarizers, 45° apart
Apr
22
asked Three polarizers, 45° apart
Oct
17
asked Adiabatic expansion
Oct
10
awarded  Student
Oct
9
accepted Work Done by an Adiabatic Expansion
Oct
9
comment Work Done by an Adiabatic Expansion
If I use $pV = RT$, then $p = \frac{RT}{V}$. Using $\delta w = pdV$, then $w = RT \int{\frac{1}{V}} dV$. Solving this gives me $w = RT\ln(5)$, which, after plugging numbers in, gives me $w = (287)(293)\ln5 = 1.35339 * 10^5$. And I was just sent an email saying that the book's answer is wrong and this one is correct. Thank you so much for your help, I really appreciate it (and I do completely get it now)!
Oct
9
asked Work Done by an Adiabatic Expansion
Oct
9
awarded  Scholar
Oct
9
accepted Work Done in an Isobaric Process
Oct
9
comment Work Done in an Isobaric Process
Wait -- is it really as simple as $(RT)/P=V$ (which gives me the change since one is 0°)? It would be divided by $p$ and then again multiplied by that, so they cancel out. This actually gives what the book says is the right answer.
Oct
9
awarded  Editor
Oct
9
revised Work Done in an Isobaric Process
deleted 14 characters in body
Oct
9
asked Work Done in an Isobaric Process